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Nitration of 1.70 g of methyl benzoate (M_r = 136.0) produces methyl 3-nitrobenzoate (M_r = 181.0) - AQA - A-Level Chemistry - Question 29 - 2021 - Paper 3
Question 29
Nitration of 1.70 g of methyl benzoate (M_r = 136.0) produces methyl 3-nitrobenzoate (M_r = 181.0). The percentage yield is 65.0%. What mass, in g, of methyl 3-nit... show full transcript
Worked Solution & Example Answer:Nitration of 1.70 g of methyl benzoate (M_r = 136.0) produces methyl 3-nitrobenzoate (M_r = 181.0) - AQA - A-Level Chemistry - Question 29 - 2021 - Paper 3
Step 1
Step 2
Determine the theoretical yield of methyl 3-nitrobenzoate
Answer
Since the reaction produces 1 mole of methyl 3-nitrobenzoate per mole of methyl benzoate, the theoretical moles of methyl 3-nitrobenzoate produced is also 0.0125 mol.
Now, calculate the mass of methyl 3-nitrobenzoate using:
where M_r = 181.0 g/mol.
Calculating:
Step 3
Adjust for percentage yield
Answer
Since the percentage yield is 65.0%, the actual yield can be calculated as:
Using the theoretical yield from the previous step: ext{Actual yield} = 2.2625 imes rac{65.0}{100} = 1.471625 ext{ g} Rounding to two decimal places, the mass of methyl 3-nitrobenzoate produced is approximately 1.47 g.