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Question 9
Fluoride ions are produced by the addition of a single electron to an atom of fluorine \(^{19}F\). What is the magnitude of specific charge of the fluoride ion?
Step 1
Answer
To determine the specific charge of the fluoride ion ( ext{F}^{-}), we first need to understand that fluoride ions are formed by adding an electron to fluorine. The specific charge can be calculated using the formula:
where (Q) is the charge of the ion and (m) is its mass. The charge of the electron is approximately (-1.6 \times 10^{-19}) C. The mass of a fluoride ion can be approximated using the mass of (^{19}F), which is around (3.19 \times 10^{-26}) kg.
Now, substituting these values in:
Thus, the correct answer for the magnitude of specific charge of the fluoride ion is:
C. 5.0 x 10^6 C kg⁻¹
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