The diagram shows a bullet moving towards a wooden block. The bullet is moving with a velocity of 170 m/s. The mass of the bullet is 0.030 kg. Show that the momentum of the bullet is about 5.0 kg m/s. The bullet collides with the wooden block and sticks in it. The bullet and the wooden block move off together. The mass of the wooden block is 0.80 kg. Calculate the velocity of the wooden block and bullet immediately after the collision.

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The diagram shows a bullet moving towards a wooden block - Edexcel - GCSE Physics - Question 4 - 2013 - Paper 1

Question 4

The diagram shows a bullet moving towards a wooden block. The bullet is moving with a velocity of 170 m/s. The mass of the bullet is 0.030 kg. Show that the moment... show full transcript

Worked Solution & Example Answer:The diagram shows a bullet moving towards a wooden block - Edexcel - GCSE Physics - Question 4 - 2013 - Paper 1

Step 1

The bullet is moving with a velocity of 170 m/s. The mass of the bullet is 0.030 kg. Show that the momentum of the bullet is about 5.0 kg m/s.

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Answer

To find the momentum of the bullet, we use the formula:

ext{Momentum} = ext{mass} imes ext{velocity}

Substituting the known values:

ext{Momentum} = 0.030 \, ext{kg} imes 170 \, ext{m/s} = 5.1 \, ext{kg m/s}

Thus, we have shown that the momentum of the bullet is approximately 5.0 kg m/s.

Step 2

The bullet collides with the wooden block and sticks in it. Calculate the velocity of the wooden block and bullet immediately after the collision.

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Answer

To calculate the velocity after the collision, we will apply the principle of conservation of momentum:

ext{momentum before} = ext{momentum after}

Calculating the total momentum before the collision:

ext{momentum before} = 5.1 \, ext{kg m/s} ext{ (from bullet)} + 0 \, ext{kg m/s} ext{ (from block)} = 5.1 \, ext{kg m/s}

After the collision, the combined mass is:

ext{mass after} = 0.030 \, ext{kg} + 0.80 \, ext{kg} = 0.83 \, ext{kg}

Now, applying the conservation of momentum:

5.1 \, ext{kg m/s} = 0.83 \, ext{kg} imes v

Solving for the velocity $v$ :

v = rac{5.1 \, ext{kg m/s}}{0.83 \, ext{kg}} \ = 6.14 \, ext{m/s} ext{ (approximately 6.1 m/s)}

Thus, the velocity of the wooden block and bullet immediately after the collision is approximately 6.1 m/s.

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The diagram shows a bullet moving towards a wooden block - Edexcel - GCSE Physics - Question 4 - 2013 - Paper 1

Worked Solution & Example Answer:The diagram shows a bullet moving towards a wooden block - Edexcel - GCSE Physics - Question 4 - 2013 - Paper 1

The bullet is moving with a velocity of 170 m/s. The mass of the bullet is 0.030 kg. Show that the momentum of the bullet is about 5.0 kg m/s.

The bullet collides with the wooden block and sticks in it. Calculate the velocity of the wooden block and bullet immediately after the collision.

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