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7.1 Explain what an operational amplifier (op amp) is - NSC Electrical Technology Electronics - Question 7 - 2017 - Paper 1

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7.1 Explain what an operational amplifier (op amp) is. 7.2 State TWO advantages of using integrated circuits (such as op amps) over discrete components (circuits b... show full transcript

Worked Solution & Example Answer:7.1 Explain what an operational amplifier (op amp) is - NSC Electrical Technology Electronics - Question 7 - 2017 - Paper 1

Step 1

Explain what an operational amplifier (op amp) is.

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Answer

An operational amplifier (op amp) is an integrated circuit that serves as a high-gain voltage amplifier. It has two input terminals, inverting and non-inverting, and one output terminal. The op amp amplifies the difference between the input signals and is characterized by a very high open-loop voltage gain, typically exceeding 100,000.

Step 2

State TWO advantages of using integrated circuits (such as op amps) over discrete components (circuits built with individual components).

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Answer

  1. Integrated circuits are cheaper to manufacture due to mass production processes.
  2. They are more versatile, allowing for compact designs and reducing the overall space required for circuit implementations.

Step 3

Describe how a differential amplifier works.

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Answer

A differential amplifier amplifies the voltage difference between two input signals. The output voltage is given by the equation:

Vout=Ad(Vin+Vin)V_{out} = A_d (V_{in+} - V_{in-})

where AdA_d is the differential gain of the amplifier. It can also provide a common-mode rejection, allowing it to effectively suppress any signals that are common to both inputs.

Step 4

Name the type of feedback found in the following circuits: 7.4.1 Amplifier circuits.

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Answer

Negative feedback is commonly used in amplifier circuits to stabilize gain and improve linearity.

Step 5

Name the type of feedback found in the following circuits: 7.4.2 Oscillator circuits.

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Answer

Positive feedback is typically found in oscillator circuits to maintain oscillation.

Step 6

Explain the difference between positive feedback and negative feedback.

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Answer

Positive feedback amplifies the input signal, which can lead to increased gain but may cause instability or oscillation. Negative feedback reduces the gain and stabilizes the output, improving linearity and bandwidth.

Step 7

Calculate the output voltage of the amplifier.

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Answer

Using the given values: Vin=0.7extV,Rf=170extkΩ,Rin=10extkΩV_{in} = 0.7 ext{ V}, R_f = 170 ext{ kΩ}, R_{in} = 10 ext{ kΩ}

The output voltage can be calculated as:

Vout=Vin(1+RfRin)=0.7V(1+17010)12.6VV_{out} = V_{in} \left(1 + \frac{R_f}{R_{in}}\right) = 0.7 V \left(1 + \frac{170}{10}\right) \approx 12.6 V

Step 8

Calculate the voltage gain of the amplifier.

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Answer

The voltage gain AvA_v is calculated using:

Av=RfRin=170,00010,000=17A_v = -\frac{R_f}{R_{in}} = -\frac{170,000}{10,000} = -17

Step 9

Describe the function of an inverting op amp.

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Answer

An inverting operational amplifier produces an output that is 180 degrees out of phase with the input signal. It inverts the input signal and provides a proportional output based on the ratio of the feedback resistor to the input resistor.

Step 10

Give ONE application of a monostable multivibrator.

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Answer

One application of a monostable multivibrator is used in timer circuits where a single pulse is generated in response to an input trigger.

Step 11

Explain the main difference between a monostable multivibrator and a bi-stable multivibrator.

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Answer

A monostable multivibrator has one stable state and converts a trigger pulse into a single output pulse, while a bi-stable multivibrator has two stable states and can maintain its state until a trigger pulse changes it.

Step 12

7.10.1 INTEGRATOR OP AMP: Redraw the input waveforms.

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The integrator op amp takes a step input signal and produces a ramp output. This can be represented graphically with the input waveform being stepped and the output showing a continuous ramp.

Step 13

7.10.2 INPUT WAVEFORM FOR INVERTING COMPARATOR OP AMP: Redraw the input waveforms.

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For the inverting comparator, the output remains at one stable state until the input crosses the reference voltage, resulting in a square wave output.

Step 14

7.10.3 INPUT WAVEFORM FOR INVERTING SCHMITT TRIGGER OP AMP: Redraw the input waveforms.

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The Schmitt trigger applies hysteresis to provide noise margins. The output switches states based on the upper and lower trigger levels of the input signal.

Step 15

7.11 Redraw the input waveforms of an inverting summing op amp.

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The summing op amp output will be a weighted sum of the input waveforms, where each input is inverted and summed to produce a single output waveform.

Step 16

Calculate the output voltage of the amplifier in FIGURE 7.12.

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Answer

Using: Vout=RfRinVin=200k20k5V=50VV_{out} = -\frac{R_f}{R_{in}} \cdot V_{in} = -\frac{200k}{20k} \cdot 5V = -50V

Step 17

Calculate the gain of the amplifier.

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Answer

The gain is calculated in the same manner as the output voltage: Av=RfRin=10A_v = -\frac{R_f}{R_{in}} = -10

Step 18

State ONE application of a Schmidt trigger.

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Answer

A Schmidt trigger is often used in signal conditioning to eliminate noise from a signal and to create clean digital transitions.

Step 19

Calculate the resonant frequency of the Hartley oscillator.

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Answer

The resonant frequency ff is given by: f=12πLCf = \frac{1}{2\pi\sqrt{LC}} For L=27 mHL = 27 \text{ mH} and C=47μFC = 47 \mu F, substituting values we find: f=12π(27×103)(47×106)141.28Hzf = \frac{1}{2\pi\sqrt{(27 \times 10^{-3})(47 \times 10^{-6})}} \approx 141.28 Hz

Step 20

Calculate the frequency of the RC phase-shift oscillator.

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The frequency ff of the oscillator can be calculated by the formula: f=12πRCf = \frac{1}{2\pi RC} For resistors R=25kΩR = 25k\Omega and capacitors C=45pFC = 45 pF, the total frequency can be computed as: f=12π(25×103)(45×1012)57.76kHzf = \frac{1}{2\pi (25 \times 10^{3})(45 \times 10^{-12})} \approx 57.76 kHz

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