Refer to Figure 7.4 below and answer the questions that follow. - NSC Electrical Technology Electronics - Question 3 - 2017 - Paper 1

The primary current can be calculated using:

$I_P = \frac{S}{\sqrt{3} V_P}$

Where:

$I_P = \frac{25000}{\sqrt{3} \times 6000} = 2.40 A$

The phase current is found from:

$I_{Ph} = \frac{I_L}{\sqrt{3}}$

Therefore:

$I_{Ph} = \frac{2.40}{\sqrt{3}} = 1.38 A$

The turns ratio is calculated using:

$TR = \frac{N_S}{N_P} = \frac{I_{S}}{I_{Ph}}$

Thus:

$TR \approx 27.5 : 1$

The transformer can serve both single-phase and three-phase loads due to the availability of the neutral point.

Regular maintenance is crucial as it ensures the efficiency of the transformer and prolongs its lifespan. Maintenance also aids in identifying and detecting any abnormal functions.