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3.1 What is the purpose of a transformer? 3.2 Name the type of loss that is dissipated in a transformer due to the internal resistance in the windings - NSC Electrical Technology Electronics - Question 3 - 2017 - Paper 1

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3.1 What is the purpose of a transformer? 3.2 Name the type of loss that is dissipated in a transformer due to the internal resistance in the windings. 3.3 State T... show full transcript

Worked Solution & Example Answer:3.1 What is the purpose of a transformer? 3.2 Name the type of loss that is dissipated in a transformer due to the internal resistance in the windings - NSC Electrical Technology Electronics - Question 3 - 2017 - Paper 1

Step 1

What is the purpose of a transformer?

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Answer

The purpose of a transformer is to change the voltage level of alternating current (AC) in an electrical circuit while maintaining the power (minus losses) flowing through it. It can either step-up (increase) or step-down (decrease) the voltage as required by the application.

Step 2

Name the type of loss that is dissipated in a transformer due to the internal resistance in the windings.

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Answer

The type of loss dissipated due to internal resistance in the windings of a transformer is called copper loss or I²R loss, which occurs due to the resistance of the wires that carry the current.

Step 3

State TWO methods used to cool transformers.

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Answer

  1. Oil cooling: Uses transformer oil to dissipate heat from the windings and core.
  2. Air cooling: Utilizes fans or natural convection to remove heat from the transformer.

Step 4

Describe what could happen if one of the cooling methods used to cool large transformers failed to perform its function.

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Answer

If a cooling method fails, the transformer may overheat. This overheating can lead to insulation breakdown and short circuits, resulting in transformer failure or reduced operational life, and can also pose a fire hazard.

Step 5

Name TWO applications of a three-phase delta-star transformer.

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Answer

  1. Industrial power distribution: They are used to convert high-voltage electricity from the grid into lower voltage for factory operations.
  2. Power generation plants: They allow the distribution of electricity generated from wind or solar farms in a suitable voltage for consumer usage.

Step 6

Secondary line current

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Answer

To determine the secondary line current, use the formula:

IL=S3VLI_L = \frac{S}{\sqrt{3} V_{L}}

Substituting the values:

IL=1200003×380182.32AI_L = \frac{120000}{\sqrt{3} \times 380} \approx 182.32 A

Step 7

Secondary phase current

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Answer

The secondary phase current can be found using the line current:

Iph=ILI_{ph} = I_L

Thus,

Iph=182.32AI_{ph} = 182.32 A

Step 8

Input power to the clinic

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Answer

The input power can be calculated using the formula:

P=3VLILcosθP = \sqrt{3} V_{L} I_{L} \cos \theta

Substituting the known values:

P=3×380×182.32×0.9107999.32WP = \sqrt{3} \times 380 \times 182.32 \times 0.9 \approx 107999.32 W

Step 9

Explain why the secondary winding of a step-down transformer has a thicker wire.

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Answer

The secondary winding of a step-down transformer has a thicker wire because it carries a higher current than the primary winding due to the step-down voltage transformation. Thicker wires can handle the increased current, helping to reduce resistive losses and prevent overheating.

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