4.1 Name ONE mode of operation of the metal-oxide-semiconductor field-effect transistor (MOSFET) - NSC Electrical Technology Electronics - Question 4 - 2021 - Paper 1
Question 4
4.1 Name ONE mode of operation of the metal-oxide-semiconductor field-effect transistor (MOSFET).
4.2 Refer to FIGURE 4.2 below and answer the questions that follow... show full transcript
Worked Solution & Example Answer:4.1 Name ONE mode of operation of the metal-oxide-semiconductor field-effect transistor (MOSFET) - NSC Electrical Technology Electronics - Question 4 - 2021 - Paper 1
Step 1
4.1 Name ONE mode of operation of the metal-oxide-semiconductor field-effect transistor (MOSFET).
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Answer
Enhancement Mode MOSFET.
Step 2
4.2.1 Identify the semiconductor symbol in FIGURE 4.2.
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Answer
The semiconductor symbol in FIGURE 4.2 is that of a MOSFET, specifically a P-channel enhancement mode.
Step 3
4.2.2 Explain how the metal-oxide-semiconductor field-effect transistor (MOSFET) differs from the junction field-effect transistor (JFET) with reference to its construction.
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The MOSFET has a metal-oxide layer that provides insulation between the gate electrode and the channel, while in a JFET, the gate and the channel are physically connected.
Step 4
4.3.1 Identify pulses B2.
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Pulses B2 are Sawtooth pulses.
Step 5
4.3.2 Explain the term saturation region with reference to the operation of the UJT.
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The saturation region occurs when the operating point has fallen beyond the valley point, and the emitter has been supplied with sufficient current.
Step 6
4.3.3 Describe how the UJT is driven into the CUT-OFF mode.
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The UJT is driven into the cut-off mode when the voltage across the capacitor falls to the UJT's emitter-base junction, consequently resetting the conditions.
Step 7
4.3.4 Draw the output voltage waveform across R2 on the ANSWER SHEET for QUESTION 4.3.4.
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A sketch of the output voltage waveform across R2 should reflect the behavior of the UJT circuit, showing the transition between cut-off and saturation.
Step 8
4.4.1 Identify the circuit diagram in FIGURE 4.4.
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The circuit diagram in FIGURE 4.4 is a Darlington transistor amplifier.
Step 9
4.4.2 Describe how the transistors are biased and fully turned ON by referring to the required voltages.
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To fully turn on the transistors, a supply voltage exceeding 1.4 V is connected to the base of the Darlington transistor, ensuring sufficient biasing of both the base-emitter and collector-emitter junctions.
Step 10
4.4.3 State TWO advantages of the circuit in FIGURE 4.4.
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It can supply high current gain.
It has improved input impedance, reducing load on the preceding stages.
Step 11
4.4.4 Explain why the transistor in FIGURE 4.4 is preferred over a single transistor when used as a switch.
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A Darlington transistor is preferred because it can energize and operate switching devices that demand higher current.
Step 12
4.5.1 Identify the type of operational amplifier in FIGURE 4.5.
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The operational amplifier in FIGURE 4.5 is a Non-Inverting Operational Amplifier.
Step 13
4.5.2 Draw the output voltage waveform on the ANSWER SHEET for QUESTION 4.5.2.
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The output waveform should show the amplified response with a phase shift of zero from the input signal.
Step 14
4.5.3 Explain why operational amplifiers are known as differential voltage amplifiers.
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Operational amplifiers amplify the difference in voltage between two input signals, which makes them effective as differential amplifiers.
Step 15
4.6.1 Explain the function of the RS flip-flop.
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The RS flip-flop stores the last received information until new information is provided by its two stable states.
Step 16
4.6.2 State the typical operating voltage range of the 555 IC.
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+5 V to (+15 V or +18 V).
Step 17
4.6.3 Name TWO modes of operation for the 555 IC.
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Astable Mode
Monostable Mode.
Step 18
4.6.5 Explain the function of the threshold input on Pin 6 of 555 Timer IC.
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The threshold input monitors the voltage at which a 555 IC will reset when the voltage exceeds
rac{1}{3} V_{CC}.
Step 19
4.7 Refer to FIGURE 4.7 below and explain why the output is zero volts.
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The output of the 741 Op-Amp is zero volts due to equal amplitudes at both inputs, causing cancellation.
Step 20
4.8.1 Calculate the output voltage.
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Given the values, the output voltage can be calculated using the formula:
Vout=Vin(1+RnRf)
Substituting, we find:
Vout=2.5mV(1+2.2110)=127.5mV.
Step 21
4.8.2 Explain the effect on the output when the value of the feedback resistor is equal to that of the input resistor.
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When the feedback resistor is equal to the input resistor, the output voltage will be twice that of the input voltage.