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5.1 Describe the term impedance with reference to an RLC circuit - NSC Electrical Technology Electronics - Question 5 - 2017 - Paper 1

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5.1 Describe the term impedance with reference to an RLC circuit. 5.2 FIGURE 5.2 below shows the phasor diagram of a series RLC circuit. Answer the questions that f... show full transcript

Worked Solution & Example Answer:5.1 Describe the term impedance with reference to an RLC circuit - NSC Electrical Technology Electronics - Question 5 - 2017 - Paper 1

Step 1

5.1 Describe the term impedance with reference to an RLC circuit.

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Answer

Impedance is defined as the total opposition offered to the flow of current when an RLC circuit is connected across an alternating voltage supply. It combines resistance and reactance in a circuit, affecting how current and voltage behave.

Step 2

5.2.1 With reference to current and voltage, explain whether the circuit is inductive or capacitive.

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Answer

In the phasor diagram, the voltage across the inductor, VL=80VV_L = 80 V, is greater than the voltage across the capacitor, VC=50VV_C = 50 V. This leads to a situation where the current ITI_T will lag the voltage VSV_S, indicating that the circuit is inductive.

Step 3

5.2.2 Describe how an increase in frequency will affect $V_L$.

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Answer

If the frequency of the supply is increased, the inductive reactance XLX_L of the coil will also increase, as XLX_L is directly proportional to the frequency of the supply. This results in an increase in the voltage across the inductor VLV_L.

Step 4

5.2.3 Calculate the total voltage.

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Answer

The total voltage VTV_T can be calculated using the formula:

ho imes ext{Resultant Voltage}$$ where the resultant voltage is given by: $$V_f = rac{1}{ ho} imes ext{Square Root of } [ (V_R)^2 + (V_L - V_C)^2 ]$$ Substituting the values: $$V_T = ext{sqrt}(110^2 + (80 - 50)^2) \\ = ext{114.02 V}$$

Step 5

5.3.1 Total current.

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Answer

To find the total current ITI_T, we apply the formula: IT=extsqrt(IR2+(ILIC)2)=extsqrt(52+(64)2)=5.39AI_T = ext{sqrt}(I_R^2 + (I_L - I_C)^2) \\ = ext{sqrt}(5^2 + (6 - 4)^2) \\ = 5.39 A

Step 6

5.3.2 Phase angle.

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Answer

The phase angle θ\theta can be calculated using: θ=cos1(IRIT)=cos1(55.39)=21.93\theta = \cos^{-1}\left(\frac{I_R}{I_T}\right) \\ = \cos^{-1}\left(\frac{5}{5.39}\right) \\ = 21.93^\circ

Step 7

5.3.3 Inductive reactance.

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Answer

The inductive reactance can be calculated using: XL=VTIL=2406=40ΩX_L = \frac{V_T}{I_L} \\ = \frac{240}{6} \\ = 40 \Omega

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