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Refer to Figure 2.2 below and answer the questions that follow - NSC Electrical Technology Power Systems - Question 4 - 2017 - Paper 1

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Refer to Figure 2.2 below and answer the questions that follow. --- **Figure 2.2**: Three-Phase Motors and Starters ---

Worked Solution & Example Answer:Refer to Figure 2.2 below and answer the questions that follow - NSC Electrical Technology Power Systems - Question 4 - 2017 - Paper 1

Step 1

4.1 What advantages do three-phase motors have over single-phase motors?

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Answer

Three-phase motors require less maintenance compared to single-phase motors because they have fewer parts. Additionally, for motors of the same size frame, three-phase motors deliver a higher torque, which enhances their performance in various applications.

Step 2

4.2 What are the consequences of starting a three-phase motor if the rotor is not rotating freely?

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Answer

If the rotor is not rotating freely and is switched on, it may cause extensive damage to both the motor and the operator. This is due to the high starting currents that can lead to overheating and potential mechanical failure.

Step 3

4.3 What checks should be performed on electrical connections before operating the motor?

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Answer

It is crucial to ensure that all electrical connections are secure. Moreover, the insulation resistance between the windings and the earth should be tested to prevent any short circuits, which could pose a safety hazard.

Step 4

4.4 What does an electrical fault between the rotor and stator indicate?

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Answer

An electrical connection indicating a short circuit between the rotor and stator signifies a fault condition. This can potentially cause damage to the motor if not addressed immediately.

Step 5

4.5 Explain the types of losses in a three-phase motor.

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Answer

In a three-phase motor, there are mechanical losses, which include friction and windage losses, and iron losses, which are associated with the hysteresis and eddy currents in the motor core. These losses can impact the efficiency and performance of the motor.

Step 6

4.6.1 Calculate the output power when the input power is 15,000 W and the power factor is 0.8.

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Answer

The output power can be calculated using the formula:
Pout=5imesextcoshetaP_{out} = 5 imes ext{cos} heta
Substituting the values, we get:
Pout=15,000Wimes0.8=12,000WP_{out} = 15,000 W imes 0.8 = 12,000 W
Thus, the output power is 12 kW.

Step 7

4.7.1 How does improving the power factor affect motor performance?

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Answer

Improving the power factor will allow more power to be available to do the work required of the motor, enhancing its operational efficiency.

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