2.1 Define the following with reference to RLC circuits:
2.1.1 Power factor
2.1.2 Q-factor of an inductor in a resonant circuit
2.2 State TWO applications of RLC circuits - NSC Electrical Technology Power Systems - Question 2 - 2019 - Paper 1
Question 2
2.1 Define the following with reference to RLC circuits:
2.1.1 Power factor
2.1.2 Q-factor of an inductor in a resonant circuit
2.2 State TWO applications of RLC... show full transcript
Worked Solution & Example Answer:2.1 Define the following with reference to RLC circuits:
2.1.1 Power factor
2.1.2 Q-factor of an inductor in a resonant circuit
2.2 State TWO applications of RLC circuits - NSC Electrical Technology Power Systems - Question 2 - 2019 - Paper 1
Step 1
2.1.1 Power factor
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Answer
The power factor is the ratio of the true power (measured in watts) to the apparent power (measured in volt-amperes) in an AC circuit. Mathematically, it can be represented as:
ext{Power Factor} = rac{P}{S}
where P is the real power and S is the apparent power.
Step 2
2.1.2 Q-factor of an inductor in a resonant circuit
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Answer
The Q-factor, or quality factor, of an inductor in a resonant circuit measures the inductor's efficiency. It is defined as the ratio of its inductive reactance to its internal resistance:
Q = rac{X_L}{R}
where XL is the inductive reactance.
Step 3
2.2 State TWO applications of RLC circuits
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Answer
RLC circuits are used in radio receivers to tune into specific frequencies.
They are also used in filter circuits to allow certain frequency ranges to pass while attenuating others.
Step 4
2.3.1 Calculate the total voltage of the supply
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Answer
To calculate the total voltage of the supply, use the formula:
2.3.2 Calculate the value of the inductive reactance
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Answer
The inductive reactance XL can be calculated using the formula:
XL=ILimesR
Here,
X_L = rac{V_L}{I_T} = rac{16V}{3A} = 5.33 ext{ Ω}
Step 6
2.3.3 State if the circuit is capacitive or inductive. Motivate your answer.
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The circuit is capacitive because the voltage drop across the capacitor (VC=24V) is greater than the voltage across the inductor (VL=16V). Therefore, the behavior of the circuit is primarily influenced by the capacitor.
Step 7
2.4.1 Calculate the total current in the circuit
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The total current in the circuit can be calculated using:
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Answer
The phase angle heta can be calculated using:
heta = ext{Cos}^{-1}igg(rac{I_R}{I_T}igg)
Substituting the known values:
heta = ext{Cos}^{-1}igg(rac{6}{6.08}igg)
ightarrow ≈ 9.30°
Step 9
2.4.3 State whether the phase angle is leading or lagging. Motivate your answer.
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The phase angle is lagging because the inductive current (IL) is greater than the capacitive current (IC). This indicates that the inductive component is dominant in the circuit.
Step 10
2.5.1 Calculate the value of C when the circuit resonates at 2 kHz
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At resonance, XL=XC. The resonance condition in terms of capacitance can be given by:
2.5.2 Calculate the value of the current in the circuit
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Answer
At resonance, the impedance Z equals the resistance R:
I = rac{V_T}{Z} = rac{120V}{12Ω} = 10 A
Step 12
2.5.3 State how current will be affected if the resistance is doubled.
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If the resistance is doubled, the current will be halved. This is because the total impedance will increase, thereby reducing the current according to Ohm's law.
Step 13
2.5.4 List THREE characteristics of an RLC series circuit at resonance.
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The impedance is at a minimum, equal only to the resistance R.
The phase angle is zero degrees, meaning voltage and current are in phase.