3.1 Definieer kapasitiewe reaksie met verwysing na RLC-kring - NSC Electrical Technology Power Systems - Question 3 - 2021 - Paper 1
Question 3
3.1 Definieer kapasitiewe reaksie met verwysing na RLC-kring.
Kapasitiewe reaksie is die weerstand wat 'n kapasitor teen die vloei van wisselstroom bied in 'n WS-k... show full transcript
Worked Solution & Example Answer:3.1 Definieer kapasitiewe reaksie met verwysing na RLC-kring - NSC Electrical Technology Power Systems - Question 3 - 2021 - Paper 1
Step 1
3.1 Definieer kapasitiewe reaksie met verwysing na RLC-kring.
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Kapasitiewe reaksie is die weerstand wat 'n kapasitor teen die vloei van wisselstroom bied in 'n WS-kring.
Step 2
3.2 Noem die faseverhouding tussen die stroom en spanning in 'n suiwer induktiewe WS-kring.
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Daar is 'n 90° faseverskuiwing tussen VL en IL, waar IL met 90° loop.
Step 3
3.3.1 Bereken die induktansie van die induktor.
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L=2πfXL=2π(60)150=0.40H
Step 4
3.3.2 Bereken die impedansie van die kring.
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Z=R2+(XL−XC)2=602+(150−120)2=67.08Ω
Step 5
3.3.3 Bereken die drywingfaktor.
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cosϕ=ZR=67.0860=0.89
Step 6
3.3.4 Noem DRIE toestande wat sal ontstaan indien die drywingfaktor in 'n RLC-seriekring eenheidswaarde bereik.
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R=Z; Fasehoek = 0°; IL = IC = I is maksimum.
Step 7
3.4.1 Bepaal die resonansiefrekwensie in FIGUUR 3.4 A.
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800kHz
Step 8
3.4.2 Vergelyk die waardes van die induktiewe reaksie en kapasitiewe reaksie wanneer die frekwensie van 200 Hz na 1 600 Hz toeneem.
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Wanneer die frekwensie van 200 Hz na 1 600 Hz toeneem, sal die XL toeneem en die XC sal afneem.
Step 9
3.4.3 Bereken die spanningsval oor die induktor as die frekwensie 600 Hz is.
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VL=IL×XL=0.66×750=495μV
Step 10
3.4.4 Bereken die waarde van die kapasitor deur die reaksiewaarde by 600 Hz te gebruik.
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C=2πfXC1=2π(600)(1333)1=198.99×10−9F
Step 11
3.5.1 Bereken die totale stroomvloei deur die kringbaan.
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Tydens resonansie is Z=R=20Ω. I=ZVf=20220=11A
Step 12
3.5.2 Bereken die spanningsval oor die induktor.
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VL=I×XL=11×50=550V
Step 13
3.5.3 Bereken die Q-faktor van die kring.
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