6.1 Name THREE parts of a cage rotor - NSC Electrical Technology Power Systems - Question 6 - 2023 - Paper 1
Question 6
6.1 Name THREE parts of a cage rotor.
6.2 Refer to FIGURE 6.2 below and answer the questions that follow.
6.2.1 Identify point X.
6.2.2 Define the term rotor slip... show full transcript
Worked Solution & Example Answer:6.1 Name THREE parts of a cage rotor - NSC Electrical Technology Power Systems - Question 6 - 2023 - Paper 1
Step 1
Identify point X.
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Answer
Point X represents the synchronous speed of the rotor, where the rotor is moving at the same speed as the magnetic field generated by the stator.
Step 2
Define the term rotor slip.
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Answer
Rotor slip is defined as the difference between the synchronous speed and the rotor speed, expressed as a percentage of the synchronous speed. It is given by the formula:
ext{Slip} = rac{n_s - n_r}{n_s} imes 100
where ns is the synchronous speed and nr is the rotor speed.
Step 3
Synchronous speed.
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The synchronous speed (ns) of a motor can be calculated using the formula:
n_s = rac{60 imes f}{p}
Substituting the values:
n_s = rac{60 imes 50}{4} = 750 ext{ r/min}
Step 4
Rotor speed if the slip is 5%.
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To calculate the rotor speed (nr) with a slip of 5%, we can use the formula:
n_r = n_s - rac{ ext{Slip} imes n_s}{100}
Calculating:
n_r = 750 - rac{5 imes 750}{100} = 712.5 ext{ r/min}
Step 5
Combined true power of the two motors.
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The combined true power (Pt) is given by:
Pt=P1+P2=75extkW+50extkW=125extkW
Step 6
Combined reactive power of the two motors.
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The combined reactive power (Qt) is obtained by adding the reactive powers:
Qt=Q1+Q2=45extkVAr+21.79extkVAr=66.79extkVAr
Step 7
Apparent power after Motor 2 was added to the system.
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The apparent power (S) can be calculated using:
S = rac{(P_t)^2 + (Q_t)^2}{ ext{VA}}
Calculating:
S = rac{(125,000)^2 + (66,790)^2}{ ext{VA}} = 141.72 ext{ kVA}
Step 8
Power factor of the system after Motor 2 was added.
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The power factor (extpf) can be calculated as:
ext{pf} = rac{P_t}{S} = rac{125,000}{141.72 imes 1,000} = 0.88
Step 9
Name the contacts that create the interlocking function in the circuit above.
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The contacts that create the interlocking function are MC1 N/C and MC2 N/C.
Step 10
Explain why a normally closed contact of the overload is used and not a normally open contact.
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A normally closed contact allows current to flow under normal operating conditions. If an overload condition occurs, the contact will open, cutting off the current and protecting the motor from damage.
Step 11
Referring to the control mechanisms in the control circuit, explain why MC2 cannot be energised at the same time as MC1.
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MC2 cannot be energised at the same time as MC1 because the interlocking contact (MC1 N/C) is wired in series with the control circuit for MC2. When MC1 is engaged, the N/C contact for MC1 will open, preventing the energisation of MC2.
Step 12
Explain how the operation of the circuit will be affected when MC1 N/O is faulty and permanently open.
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If MC1 N/O is faulty and permanently open, it will prevent the energisation of the motor. As a result, pressing the START 1 button will not initiate motor operation, effectively disabling the motor control circuit.