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5.1 State THREE mechanical inspections to be conducted on a three-phase motor after installation, but before commissioning - NSC Electrical Technology Power Systems - Question 5 - 2020 - Paper 1

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5.1 State THREE mechanical inspections to be conducted on a three-phase motor after installation, but before commissioning. 5.2 State THREE advantages of a squirrel... show full transcript

Worked Solution & Example Answer:5.1 State THREE mechanical inspections to be conducted on a three-phase motor after installation, but before commissioning - NSC Electrical Technology Power Systems - Question 5 - 2020 - Paper 1

Step 1

5.1 State THREE mechanical inspections to be conducted on a three-phase motor after installation, but before commissioning.

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Answer

  1. Check that the bolts securing the motor to the frame are tight.

  2. Verify that the end plates are fastened properly.

  3. Inspect the bearings for smooth rotation.

Step 2

5.2 State THREE advantages of a squirrel-cage induction motor.

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Answer

  1. It is cheaper and more robust compared to other types of motors.

  2. It has slightly higher efficiency and power factor.

  3. These motors are explosion-proof since the risk of sparking is eliminated by the absence of slip rings and brushes.

Step 3

5.3.1 Identify the control circuit in FIGURE 5.3.

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The control circuit in FIGURE 5.3 consists of a sequence motor starter configured without a timer and includes the components depicted for controlling motors.

Step 4

5.3.2 Explain the function of the following components in FIGURE 5.3: (a) Stop button

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Answer

The function of the stop button is to disconnect the supply from the control circuit and stop both motors.

Step 5

5.3.2 Explain the function of the following components in FIGURE 5.3: (b) MC1 (N/O1)

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Answer

The function of MC1 (N/O1) is to allow current to flow in the parallel circuit even after the start button is released. It also maintains the circuit in contact, enabling the motor to continue running.

Step 6

5.3.3 Describe the starting sequence of the control circuit.

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Answer

  1. When start button 1 is pressed, current flows through the stop button and O/I1.

  2. MC1 (Motor 1) will energize.

  3. MC1 N/O1 and MC2 N/O2 will close, allowing Motor 1 to start running.

  4. When start button 2 is pressed, MC2 (Motor 2) will energize and close its contact, switching Motor 2 on.

  5. The two motors will run respectively.

Step 7

5.4.1 Calculate the synchronous speed.

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Answer

The synchronous speed (ns) can be calculated using the formula: n_s = rac{120 imes f}{p} Substituting the values: n_s = rac{120 imes 50}{6} = 500 ext{ rpm}

Step 8

5.4.2 Calculate the rotor speed.

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Answer

The rotor speed (nr) can be calculated using: nr=nsimes(1s)n_r = n_s imes (1 - s) Substituting the values: nr=500imes(10.05)=475extrpmn_r = 500 imes (1 - 0.05) = 475 ext{ rpm}

Step 9

5.5.1 Calculate the line current drawn from the supply.

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Answer

The line current (IL) can be calculated using: I_L = rac{ ext{P}}{ rac{ ext{√3} imes V_L imes ext{Cos} θ}{1000}} Substituting the values: I_L = rac{18000}{ rac{ ext{√3} imes 380 imes 0.8}{1000}} = 34.14 ext{ A}

Step 10

5.5.2 Calculate the apparent power of the motor.

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Answer

The apparent power (S) can be calculated using: S = rac{V_L imes I_L}{1000} Substituting the values: S = rac{ ext{√3} imes 380 imes 34.14}{1000} = 22.5 ext{ kVA}

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