Photo AI

6.1 Name TWO continuity tests to be performed on a three-phase motor - NSC Electrical Technology Power Systems - Question 6 - 2022 - Paper 1

Question icon

Question 6

6.1-Name-TWO-continuity-tests-to-be-performed-on-a-three-phase-motor-NSC Electrical Technology Power Systems-Question 6-2022-Paper 1.png

6.1 Name TWO continuity tests to be performed on a three-phase motor. 6.2 Explain the term cogging with reference to induction motors. 6.3 State TWO advantages of ... show full transcript

Worked Solution & Example Answer:6.1 Name TWO continuity tests to be performed on a three-phase motor - NSC Electrical Technology Power Systems - Question 6 - 2022 - Paper 1

Step 1

Name TWO continuity tests to be performed on a three-phase motor.

96%

114 rated

Answer

  1. Continuity test between the ends of each coil.
  2. Continuity test between the frame of the motor and earth.

Step 2

Explain the term cogging with reference to induction motors.

99%

104 rated

Answer

Cogging is the tendency of the rotor rod to remain stuck under a stator tooth due to the direct magnetic attraction between the two.

Step 3

State TWO advantages of cage-type induction motors over wound rotor-type motors with slip rings and brushes.

96%

101 rated

Answer

  1. Less maintenance due to the absence of slip rings and brushes.
  2. Explosion proof because of the absence of brushes and slip rings that cause sparking.

Step 4

Name TWO applications of squirrel-cage induction motors where constant speed and torque is essential.

98%

120 rated

Answer

  1. Cranes.
  2. Conveyor belts.

Step 5

Differentiate between synchronous speed and rotor speed.

97%

117 rated

Answer

Synchronous speed is the speed at which the magnetic field in the stator rotates, while rotor speed is the speed at which the rotor rotates in an attempt to reach the synchronous speed.

Step 6

Calculate the synchronous speed of the motor.

97%

121 rated

Answer

ns=60×fp=60×503=1000n_s = \frac{60 \times f}{p} = \frac{60 \times 50}{3} = 1000 r/min

Step 7

Calculate the percentage slip.

96%

114 rated

Answer

Percentage slip=nsnrns×100=10009501000×100=5%\text{Percentage slip} = \frac{n_s - n_r}{n_s} \times 100 = \frac{1000 - 950}{1000} \times 100 = 5\%

Step 8

Name TWO types of losses other than copper losses that influence efficiency of the motor.

99%

104 rated

Answer

  1. Iron losses.
  2. Mechanical losses.

Step 9

Calculate the efficiency of the motor.

96%

101 rated

Answer

η=PinlossesPin×100=50006005000×100=88%\eta = \frac{P_{in} - \text{losses}}{P_{in}} \times 100 = \frac{5000 - 600}{5000} \times 100 = 88\%

Step 10

Calculate the output power of the motor.

98%

120 rated

Answer

Pout=Pinlosses=5000600=4400P_{out} = P_{in} - \text{losses} = 5000 - 600 = 4400 W (or 4.4 kW)

Step 11

Identify component T.

97%

117 rated

Answer

Timer.

Step 12

Explain the purpose of having TWO overload units in the circuit.

97%

121 rated

Answer

Each overload unit monitors the current drawn by each motor independently.

Step 13

Identify the error in the circuit.

96%

114 rated

Answer

The MC1/N/O2 auxiliary contact (Hold contact) connected in parallel with the start button is omitted.

Step 14

Explain how this error affects the operation of the circuit.

99%

104 rated

Answer

The moment the start button is released, MC1 will de-energize, opening MC1/N/O2, disconnecting the parallel section of the control circuit, thereby disabling timer T1, thus MC2 will not be energized.

Join the NSC students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;