FIGURE 4.1 below is a block diagram of the national grid - NSC Electrical Technology Power Systems - Question 4 - 2021 - Paper 1
Question 4
FIGURE 4.1 below is a block diagram of the national grid. Answer the questions that follow.
4.1 Name the processes at A, B and C.
4.1.2 Draw the voltage waveforms ... show full transcript
Worked Solution & Example Answer:FIGURE 4.1 below is a block diagram of the national grid - NSC Electrical Technology Power Systems - Question 4 - 2021 - Paper 1
Step 1
Name the processes at A, B and C.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The processes can be identified as follows:
A: Generation
B: Transmission
C: Distribution
Step 2
Draw the voltage waveforms generated at A.
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The voltage waveforms can be drawn as follows:
Three sinusoidal waveforms with equal amplitude and a phase difference of 120° between each.
The waveforms will be placed on the same time axis, showing the peaks and zero crossings distinctly.
Step 3
Explain why Transformer 1 is a step-up transformer.
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Transformer 1 is a step-up transformer because it increases the voltage received from the generation process to a higher level for transmission. This is done to reduce current flow in the lines, thereby minimizing I²R losses during transmission.
Step 4
Determine the type of connection used on the secondary windings of Transformer 3 and motivate your answer.
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The type of connection used is a star connection. This configuration allows for both three-phase and single-phase equipment to be served, making it versatile for varying load types.
Step 5
Calculate the phase current.
97%
117 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The phase current can be calculated using the formula:
Iph=3IL⇒315≈8.66A
Step 6
Calculate the apparent power.
97%
121 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The apparent power (S) can be calculated using:
S=3×VL×IL⇒3×380×15≈9872.69VA≈9.87kVA
Step 7
Calculate the phase angle.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The phase angle (θ) can be calculated using:
θ=cos−1(0.9)≈25.84∘
Step 8
Calculate the reactive power.
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The reactive power (Q) is calculated using:
Q=3×VL×IL×sinθ⇒3×380×15×sin(25.84∘)≈4.3kVA
Step 9
State TWO advantages of power factor correction to the consumer.
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Reduced current drawn from the supply, leading to lower electricity bills.
Increased lifespan and reduced maintenance of equipment due to lower heat generation.
Step 10
Does the reading show a leading or lagging power factor?
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The meter shows a lagging power factor.
Step 11
State the cause of this type of reading.
97%
117 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The connected load is predominantly inductive, which results in a lagging power factor.
Step 12
State how the meter reading could be brought closer to unity.
97%
121 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
By connecting capacitors in parallel with the load or using synchronous motors, we can improve the power factor and bring the meter reading closer to unity.
Step 13
Calculate the total power of the load.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The total power of the load can be calculated as:
Pt=P1+P2=250W+460W=710W
Step 14
State TWO quantities, other than power, that can be determined by using the two-wattmeter method.
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Power factor.
Phase angle.
Step 15
Explain why the two-wattmeter method is preferred over the three-wattmeter method.
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The two-wattmeter method is simpler and easier to connect to the lines, and it is also a more economical method of load measurement.