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Verwys na FIGUUR 4.7 hieronder en antwoord die vrae wat volg - NSC Electrical Technology Power Systems - Question 4 - 2021 - Paper 1

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Verwys na FIGUUR 4.7 hieronder en antwoord die vrae wat volg. Gegee: TR = 5 : 1 Vf1 = 2 000 V S = 50 kVA Puit = 45 kW Transformatorverlies = 500 W Bereken die... show full transcript

Worked Solution & Example Answer:Verwys na FIGUUR 4.7 hieronder en antwoord die vrae wat volg - NSC Electrical Technology Power Systems - Question 4 - 2021 - Paper 1

Step 1

Sekondêre fase spanning

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Answer

Die sekondêre fase spanning kan bereken word met die formule:

V_{2} = rac{N_{2}}{N_{1}} imes V_{1}

Gegee dat die transformator verhouding (TR) 5:1 is, en V1=2000V_{1} = 2000 V, het ons:

V_{2} = rac{1}{5} imes 2000 = 400 ext{ V}

Step 2

Rendement van die transformator

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Answer

Die rendement (η \eta) van die transformator kan bereken word met die formule:

η=PuitPuit+verlies×100\eta = \frac{P_{uit}}{P_{uit} + \text{verlies}} \times 100

Met Puit=45000P_{uit} = 45000 W en verlies=500\text{verlies} = 500 W:

η=4500045000+500×100=98,9%\eta = \frac{45000}{45000 + 500} \times 100 = 98,9\%

Step 3

Arbeidsfactor van die transformator

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Answer

Die arbeidsfactor (cosθ \cos \theta) kan bereken word met die volgende formule:

cosθ=PS\cos \theta = \frac{P}{S}

Hier is P=45000P = 45000 W en S=50000S = 50000 VA:

cosθ=4500050000=0,9\cos \theta = \frac{45000}{50000} = 0,9

Step 4

Stroom deur die las getrek

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Answer

Die stroom deur die las kan bereken word met die formule:

I2=S3×V2×cosθI_{2} = \frac{S}{\sqrt{3} \times V_{2} \times \cos \theta}

Met S=50000S = 50000 VA, V2=400V_{2} = 400 V, en cosθ=0,9\cos \theta = 0,9:

I2=500003×400×0,972,17extAI_{2} = \frac{50000}{\sqrt{3} \times 400 \times 0,9} \approx 72,17 ext{ A}

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