3.1 State how eddy currents may be limited in the iron core of a transformer - NSC Electrical Technology Power Systems - Question 3 - 2016 - Paper 1
Question 3
3.1 State how eddy currents may be limited in the iron core of a transformer.
3.2 Name TWO similarities between a single-phase transformer and a three-phase transfo... show full transcript
Worked Solution & Example Answer:3.1 State how eddy currents may be limited in the iron core of a transformer - NSC Electrical Technology Power Systems - Question 3 - 2016 - Paper 1
Step 1
State how eddy currents may be limited in the iron core of a transformer.
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Answer
Eddy currents in the iron core of a transformer can be limited by laminating and insulating the core. This construction reduces the eddy current paths, effectively lowering their magnitude and minimizing energy losses.
Step 2
Name TWO similarities between a single-phase transformer and a three-phase transformer.
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Answer
Both single-phase and three-phase transformers serve the same functional operations by stepping voltage up or down. Additionally, both can be designed as either closed core or shell core types.
Step 3
State TWO factors that may cause excessive heating in a transformer.
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Answer
Insufficient ventilation can hinder heat dissipation, leading to higher temperatures.
Constant overloading causes excessive current flow, which generates more heat than the transformer can handle.
Step 4
Name TWO applications of a delta-star connected distribution network transformer.
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Answer
Supply of three-phase and single-phase electricity to commercial sites.
Providing power to industrial areas requiring robust energy supply systems.
Step 5
Explain the function of a transformer in a distribution network.
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Answer
A transformer in a distribution network serves to adjust voltage levels to suitable values for transmission and utilization. It steps down high voltage from transmission lines to lower voltage suitable for end-users, ensuring efficiency and safety in electrical distribution.
Step 6
Primary phase voltage
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Answer
Using the formula VL=VPH3, the primary phase voltage can be calculated as follows:
VPH=3VL=36600≈3810.66 V
Step 7
Secondary phase current
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Answer
The secondary phase current IPH is the same as the line current in this case, so:
IPH=IP=30extA
Step 8
Turns ratio
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