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2.1 The diagrams below represent the distribution of chromosome pair 21 as it appears in gametes at the end of meiosis II in a human male - NSC Life Sciences - Question 2 - 2018 - Paper 2

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2.1 The diagrams below represent the distribution of chromosome pair 21 as it appears in gametes at the end of meiosis II in a human male. A B C D 2.1.1 Expl... show full transcript

Worked Solution & Example Answer:2.1 The diagrams below represent the distribution of chromosome pair 21 as it appears in gametes at the end of meiosis II in a human male - NSC Life Sciences - Question 2 - 2018 - Paper 2

Step 1

Explain why the gametes represented by diagrams C and D do not have any chromosomes.

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Answer

The gametes represented by diagrams C and D do not have any chromosomes because they result from a failure of chromatids to separate during meiosis II, specifically during the anaphase stage. This phenomenon is known as nondisjunction, where sister chromatids fail to move to opposite poles of the cell, leading to gametes lacking one entire set of chromosomes.

Step 2

If gamete A is involved in fertilisation, describe how this may result in Down syndrome.

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Answer

If gamete A (which has 24 chromosomes, including an extra chromosome 21) fuses with a normal gamete containing 23 chromosomes, the resulting zygote will have 47 chromosomes total. This condition, known as trisomy 21 or Down syndrome, occurs when there are three copies of chromosome 21 instead of the usual two, leading to developmental and physical features associated with the syndrome.

Step 3

Due to the process of crossing over, the chromosomes in diagrams A and B appear different to each other.

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Step 4

Give the phenotype of individual 2.

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The phenotype of individual 2 is female without SCID.

Step 5

Give the phenotype of individual 1.

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The phenotype of individual 1 is male with SCID.

Step 6

Give the genotype of individual 3.

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Answer

The genotype of individual 3 is XᶺXᶺ.

Step 7

Explain how individual 5 inherited the disorder.

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Individual 5 inherited the disorder by receiving one copy of the Xᶺ allele from the mother, who is a carrier or affected, and the Y chromosome from the father.

Step 8

According to the extract, state ONE: Advantage of cloning.

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An advantage of cloning is that it allows for the production of organisms with desired characteristics, such as high milk yield.

Step 9

According to the extract, state ONE: Disadvantage of cloning.

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A disadvantage of cloning is that it reduces genetic variation in the offspring, which may lead to vulnerabilities in populations.

Step 10

State why the donor cell was taken from LMJC 865 and not from any other cow.

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The donor cell was taken from LMJC 865 because this cow had a high average milk production yield, ensuring the desired trait was preserved in the clone.

Step 11

State why an ear cell was used and not an ovum.

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An ear cell was used instead of an ovum because somatic cells can undergo cloning through a process called nuclear transfer, allowing for the entire genetic information to be retained.

Step 12

Briefly describe the process of cloning.

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The cloning process involves removing the nucleus from an ovum and replacing it with the nucleus from a somatic cell. The resulting zygote is then stimulated to undergo mitosis and is placed into the uterus of an adult female for development.

Step 13

State the dominant flower colour.

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Answer

The dominant flower colour is purple.

Step 14

Use cross 1 to explain your answer to QUESTION 2.4.1.

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Cross 1 demonstrated that when a purple-flowering plant is crossed with a white-flowering plant, all offspring produced (40 in total) displayed the purple phenotype. This indicates that the allele for purple flowers is dominant over the allele for white flowers.

Step 15

State Mendel's Law of Segregation.

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Mendel's Law of Segregation states that during meiosis, the two alleles for a characteristic separate so that each gamete receives only one allele for that characteristic.

Step 16

Use a genetic cross to show the genotypes of the parents in cross 2.

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In cross 2, the genotypes of the parents can be shown as follows: Parent 1 (purple) genotype: Dd; Parent 2 (white) genotype: dd. The Punnett square for this cross would show the following potential offspring genotypes: 50% Dd (purple) and 50% dd (white).

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