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Read the text below and answer the questions that follow - NSC Marine Sciences - Question 2 - 2024 - Paper 1

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Read the text below and answer the questions that follow. A deeper understanding of the characteristics of water waves is essential for designing efficient electric... show full transcript

Worked Solution & Example Answer:Read the text below and answer the questions that follow - NSC Marine Sciences - Question 2 - 2024 - Paper 1

Step 1

2.1.1 Draw a composite graph showing two separate lines to illustrate the data of this investigation indicated in the table above.

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Answer

To draw a composite graph, plot the average wavelength (m) on the Y-axis and the depth (mm) on the X-axis. Use the following steps to create the graph:

  1. Label the X-axis as 'Depth (mm)'.
  2. Label the Y-axis as 'Average Wavelength (m)'.
  3. Plot the data points from the table for average wavelength at each depth:
    • (240, 0.06)
    • (260, 0.07)
    • (280, 0.10)
    • (300, 0.12)
  4. Draw a line connecting these points to represent the relationship.
  5. Include a legend to differentiate between the layers.

Step 2

2.1.2 What would the maximum depth of orbitals (r = λ/2π) be formed at the depth of 300 mm? Show ALL calculations.

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Answer

Given that the wavelength at 300 mm depth is 0.12 m, we use the formula for orbital depth:

r=λ2πr = \frac{\lambda}{2\pi}

Substituting the values:

r=0.122π0.0191 m19.1 mmr = \frac{0.12}{2\pi} \approx 0.0191 \text{ m} \approx 19.1 \text{ mm}

Thus, the maximum depth of orbitals formed is approximately 19.1 mm.

Step 3

2.1.3 Describe the relationship between depth (mm) and average wavelength (m) as determined by this study.

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Answer

The data indicates that there is a positive correlation between depth and average wavelength. As the depth increases from 240 mm to 300 mm, the average wavelength also increases from 0.06 m to 0.12 m.

This suggests that deeper water allows for longer wavelengths of the waves, implying a direct relationship between these two variables.

Step 4

2.1.4 (a) Referring to the data, at which depth will the mechanism be most efficient? (b) Explain your answer to QUESTION 2.1.4(a).

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Answer

(a) The mechanism will be most efficient at a depth of 300 mm.

(b) At this depth, the average wave power is recorded as 5 J.s^-1. In comparison to the other depths, 300 mm has a relatively high average wave power and the highest average wavelength, which indicates that it is capable of producing more energy, enhancing the efficiency of the harvesting mechanism.

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