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Aggie and 14 friends started a stokvel in order to buy groceries - NSC Mathematical Literacy - Question 1 - 2021 - Paper 2

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Aggie and 14 friends started a stokvel in order to buy groceries. The grocery items bought will be shared equally among all the members of the stokvel. Aggie sourced... show full transcript

Worked Solution & Example Answer:Aggie and 14 friends started a stokvel in order to buy groceries - NSC Mathematical Literacy - Question 1 - 2021 - Paper 2

Step 1

1.1.1 Write down how many cans of fish each member of the stokvel will receive.

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Answer

The total quantity of canned fish purchased is 12 cans. Since there are 15 members in the stokvel, each member will receive:

extCanspermember=12 cans15 members=0.8 cans ext{Cans per member} = \frac{12 \text{ cans}}{15 \text{ members}} = 0.8 \text{ cans}

Hence, each member will receive approximately 0.8 cans.

Step 2

1.1.2 Aggie stated that she could load all these items onto her half-ton bakkie without overloading it.

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Answer

To verify whether Aggie can load all items without overloading, first, we calculate the total weight of all items:

  • Cake flour: 15 kg x 12.5 = 187.5 kg
  • Maize meal: 30 kg x 5 = 150 kg
  • Rama: 15 x 0.5 kg = 7.5 kg
  • Rice: 10 kg = 10 kg
  • Canned fish: 12 x 0.4 kg = 4.8 kg
  • Spice: Total weight of spice not provided in the table.

Assuming spices weigh negligible or not exceed 15 kg:

Total weight = 187.5 + 150 + 7.5 + 10 + 4.8 = 360 kg Since 1 ton = 1000 kg, Aggie's half-ton bakkie has a total allowed weight of** 500 kg** Since 360 kg is less than 500 kg, Claim is valid.

Step 3

1.1.3 Determine, showing ALL calculations, whether her statement is valid.

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Answer

Based on the total weight calculated above (360 kg), the vehicle can safely hold the weight without exceeding its limit of 500 kg. Therefore:

The statement that all items can be loaded onto the bakkie is valid.

Step 4

1.1.4 Calculate the total amount for 5 kg of maize meal from Wholesaler B at the end of January 2022.

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Answer

From Table 1, the price for 5 kg of maize meal from Wholesaler B is R659,70. This price needs to be adjusted for inflation:

  • 2021 price adjustment:

    • Inflation = 5.17%
    • Price in January 2021 = R659.70 x (1 + 0.0517)
    • Adjusted price = R659.70 x 1.0517 = R694.40 (approximately)

  • 2022 price adjustment:

    • Inflation = 5.3%
    • Price in January 2022 = R694.40 x (1 + 0.053)
    • Adjusted price = R694.40 x 1.053 = R732.01 (approximately)

Thus, the total amount for 5 kg of maize meal from Wholesaler B at the end of January 2022 will be about R732.01.

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