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2.1 The programme for the field events of an athletics meeting held on 12 February 2016 is shown in ANNEXURE B - NSC Mathematical Literacy - Question 2 - 2017 - Paper 1
Question 2
2.1 The programme for the field events of an athletics meeting held on 12 February 2016 is shown in ANNEXURE B. Use ANNEXURE B to answer the questions that follow. ... show full transcript
Worked Solution & Example Answer:2.1 The programme for the field events of an athletics meeting held on 12 February 2016 is shown in ANNEXURE B - NSC Mathematical Literacy - Question 2 - 2017 - Paper 1
Step 1
2.1.1 Determine the total time from the start of this meeting until the end of the last field event.
Answer
To determine the total time for the meeting, we first note that the event starts at 14:00. The last field event ends at 18:15. The time set aside for the last field events is 25 minutes. Therefore, we calculate:
End time = 18:15 + 25 minutes = 18:40
Total time from 14:00 to 18:40 can be calculated as:
Total time = 18:40 - 14:00 = 4 hours and 40 minutes or 4.67 hours.
Step 2
2.1.2 Calculate the difference in mass between the javelins used by a 19-year-old boy and a 15-year-old boy.
Answer
Let’s assume the mass of the javelin used by the 19-year-old boy is 800 g and for the 15-year-old boy, it is 600 g. Therefore, the difference in mass can be calculated as follows:
Difference in mass = 800 g - 600 g = 200 g.
Step 3
2.1.3 Determine Thabo's age (in years) and also indicate the time of his event.
Answer
Thabo was born in January 1999. If the current year is 2016, then Thabo's age can be calculated as:
Age = 2016 - 1999 = 17 years old.
Assuming his event time is recorded as 17:05, indicating he participated at that time.
Step 4
Step 5
Step 6
2.3.2 Determine the missing value C.
Answer
Using the given height ratio 5:4:3, let the height of the blocks be 5x, 4x, and 3x respectively. The total height is:
Total height = 5x + 4x + 3x = 12x.
Given the height of the podium is 37.5 cm, we can set up the equation:
12x = 37.5 cm,
solving for x gives us x = 3.125 cm. If we now calculate C, substituting the known values for the heights:
C = 22.5 - 3x = 30 cm.
Step 7
2.3.3 Calculate the volume (in cm³) of the block for the 1st position.
Answer
Using the formula for volume:
Volume = length × breadth × height.
Using the dimensions: length = 50 cm, breadth = 50 cm, height = 37.5 cm,
The volume can be calculated as:
Volume = 50 cm × 50 cm × 37.5 cm = 93,750 cm³.
Step 8
2.3.4 Calculate the height of the cylindrical tin.
Answer
The volume of the paint tin is 500 m² (or 500,000 cm³). The radius is given as 3.77 cm, so we can calculate the height:
Height = Volume / (π × (radius)²) = 500000 cm³ / (3.142 × (3.77)²).
After calculating, we find the height to be approximately 111.19 cm, rounded to the nearest cm gives us height = 111 cm.