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Thabo bakes round biscuits known as-Rb for sale - NSC Mathematical Literacy - Question 2 - 2016 - Paper 1

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Thabo bakes round biscuits known as-Rb for sale. He packs the biscuits in a cylindrical container made up of cardboard material. The diagram below shows the containe... show full transcript

Worked Solution & Example Answer:Thabo bakes round biscuits known as-Rb for sale - NSC Mathematical Literacy - Question 2 - 2016 - Paper 1

Step 1

2.1.1 Calculate the total surface area of the cardboard package required to make one cylindrical container.

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Answer

To calculate the total surface area (SA) of the cylindrical package, we use the formula:

SA=2πr2+2πrlSA = 2\pi r^2 + 2\pi rl

First, we need to find the radius (r) from the diameter: d=90 mmr=d2=902=45 mmd = 90 \text{ mm} \Rightarrow r = \frac{d}{2} = \frac{90}{2} = 45 \text{ mm}

Now, substituting the radius and the length (l = 270 mm) into the formula:

SA=2×3.142×(45)2+2×3.142×45×270SA = 2 \times 3.142 \times (45)^2 + 2 \times 3.142 \times 45 \times 270

Calculating:

  • Area of the circular ends: 2×3.142×2025=12712.352 \times 3.142 \times 2025 = 12712.35
  • Area of the curved surface: 2×3.142×45×270=76035.602 \times 3.142 \times 45 \times 270 = 76035.60

Therefore: SA=12712.35+76035.60=88747.95 mm2SA = 12712.35 + 76035.60 = 88747.95 \text{ mm}^2

The total surface area of the cardboard package required is approximately 89,075.7 mm289,075.7 \text{ mm}^2.

Step 2

2.1.2 Work out the area of the rectangular cardboard in mm².

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Answer

To find the area of the rectangular cardboard, we use the formula:

Area=length×widthArea = length \times width

Given:

  • Length = 120 cm = 1200 mm
  • Width = 60 cm = 600 mm

Substituting the values:

Area=1200×600=720000 mm2Area = 1200 \times 600 = 720000 \text{ mm}^2

Thus, the area of the rectangular cardboard is 720,000 mm2720,000 \text{ mm}^2.

Step 3

2.1.3 Use your answers in QUESTIONS 2.1.1 and 2.1.2 to determine the number of cylindrical containers that can be made from one piece of the cardboard.

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Answer

To determine the number of cylindrical containers, we divide the area of the cardboard by the surface area of one container:

Number of containers=Area of cardboardTotal surface area of one container\text{Number of containers} = \frac{Area\ of\ cardboard}{Total\ surface\ area\ of\ one\ container}

Using the values:

  • Area of cardboard: 720000 mm²
  • Total surface area of one container: 89075.7 mm²

Thus: Number of containers=72000089075.78.08\text{Number of containers} = \frac{720000}{89075.7} \approx 8.08

Rounding down, Thabo can make 8 cylindrical containers.

Step 4

2.2.1 Calculate the number of drops of water that filled a liter container.

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Answer

To find the number of drops that fill a liter container, we can use the formula:

Number of drops=3600 seconds/hour×1 hour2 seconds/drop\text{Number of drops} = \frac{3600 \text{ seconds/hour} \times 1 \text{ hour}}{2 \text{ seconds/drop}}

Calculating this:

  • Number of drops: 3600×12=1800 drops\frac{3600 \times 1}{2} = 1800 \text{ drops}

Therefore, the number of drops of water that filled a liter container is 1800 drops.

Step 5

2.2.2 Calculate the volume of one drop of water in microlitres.

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Answer

To find the volume of one drop of water, we can use the conversion from drops to microlitres:

7200 drops=1 litre=1000 mL7200 \text{ drops} = 1 \text{ litre} = 1000 \text{ mL}

Thus, 1 drop=1000 mL×1000 microlitres7200=138.89 microlitres1 \text{ drop} = \frac{1000 \text{ mL} \times 1000 \text{ microlitres}}{7200} = 138.89 \text{ microlitres}

The volume of one drop of water is approximately 138.89 microlitres.

Step 6

2.2.3 Work out the amount of water wasted from 01/01/2016 to 31/05/2016.

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Answer

To calculate the total water wasted over the specified period:

  • From 01/01/2016 to 31/05/2016 is 151 days.

Each drop corresponds to: 1 drop=138.89 microlitres1 \text{ drop} = 138.89\text{ microlitres}

Calculating the total drops in 151 days given 1800 drops/hour:

151 days×24 hours/day×1800 drops/hour=6,525,600 drops151 \text{ days} \times 24 \text{ hours/day} \times 1800 \text{ drops/hour} = 6,525,600 \text{ drops}

Calculating the total volume of water wasted: Volume=6,525,600 drops×138.89 microlitres/drop=907,200,000 microlitres=912 LVolume = 6,525,600 \text{ drops} \times 138.89 \text{ microlitres/drop} = 907,200,000 \text{ microlitres} = 912 \text{ L}

Thus, 912912 litres of water were wasted.

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