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Tumi received a bursary to study at the University of Victoria in Canada - NSC Mathematical Literacy - Question 2 - 2021 - Paper 2

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Tumi received a bursary to study at the University of Victoria in Canada. She travelled from the University of Victoria to Victoria Downtown. ANNEXURE A shows the m... show full transcript

Worked Solution & Example Answer:Tumi received a bursary to study at the University of Victoria in Canada - NSC Mathematical Literacy - Question 2 - 2021 - Paper 2

Step 1

2.1.1 In which general direction did she head from Cedar Hill Cross Road towards Crestview?

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Answer

Tumi headed Southeast (SE) from Cedar Hill Cross Road towards Crestview.

Step 2

2.1.2 Determine the distance she travelled on Fort Street.

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Answer

To determine the distance she travelled on Fort Street, we first construct the total distance traveled:

  • Starting from Cedar Hill Cross Road to Cadboro Road: 0.19 km
  • Cedar Hill Cross Road to Cadboro Road: 3.2 km
  • From Cadboro Road to Fort Street: The remaining distance to reach the final destination is found by using the total distance:

Total distance = 6.8 km, thus, distance on Fort Street = 6.8 km - (0.19 km + 3.2 km + 2.1 km) = 1.31 km.

Step 3

2.1.3 The route she travelled on after crossing Fort Street.

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Answer

After crossing Fort Street, Tumi took a slight right onto Pandora Avenue, followed by a 2.1 km drive to her destination.

Step 4

2.1.4 Calculate (in km/h) the average speed she travelled.

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Answer

To calculate Tumi's average speed, we first determine the total distance travelled, which is 6.8 km. Given that the total time taken was 12 minutes, we convert this into hours:

total ime = rac{12}{60} = 0.2 hours.

The average speed can then be calculated using:

ext{Average Speed} = rac{ ext{Distance}}{ ext{Time}} = rac{6.8 ext{ km}}{0.2 ext{ hours}} = 34 ext{ km/h}.

Step 5

2.1.5 Calculate (in metres) the difference between the distances of the two routes.

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Answer

Tumi's route via Shelburne was 12 km. The first route was 6.8 km. To find the difference in distance:

Difference = 12 km - 6.8 km = 5.2 km = 5,200 meters.

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