Tumi received a bursary to study at the University of Victoria in Canada - NSC Mathematical Literacy - Question 2 - 2021 - Paper 2
Question 2
Tumi received a bursary to study at the University of Victoria in Canada. She travelled from the University of Victoria to Victoria Downtown.
ANNEXURE A shows the m... show full transcript
Worked Solution & Example Answer:Tumi received a bursary to study at the University of Victoria in Canada - NSC Mathematical Literacy - Question 2 - 2021 - Paper 2
Step 1
2.1.1 In which general direction did she head from Cedar Hill Cross Road towards Crestview?
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Answer
Tumi headed in the South East direction from Cedar Hill Cross Road towards Crestview. This is inferred from her travel towards the described locations.
Step 2
2.1.2 Determine the distance that she travelled on Fort Street.
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Answer
From the summary of the route, the distance she travelled on Fort Street can be calculated as follows:
Total distance = 12 km = 6.8 km + Distance on Fort Street + 2.1 km
Therefore, Distance on Fort Street = 12 km - 6.8 km - 2.1 km = 3.1 km.
Step 3
2.1.3 The route she travelled on after crossing Fort Street.
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After crossing Fort Street, Tumi continued onto Pandora Avenue. She made a slight right onto this road, which is the continuation of her journey.
Step 4
2.1.4 Calculate (in km/h) the average speed she travelled.
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The average speed can be calculated using the formula:
extDistance=extSpeedimesextTime
Given the total distance is 12 km and the time taken to travel is 12 minutes, we need to convert the time to hours:
12extminutes=6012exthours=0.2exthours
Now, using the formula:
extSpeed=extTimeextDistance=0.212=60extkm/h.
Step 5
2.1.5 Calculate (in metres) the difference between the distances of the two routes.
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Answer
To find the difference in distances, we first need to determine the distance via Shelburne. Assuming it is a straight route not accounted for in the given route summary, let's denote it as 'D'.
From the first route:
Distance travelled = 12 km = 12000 m.
If we have that distance again from the Shelburne route is 36.5 km/h over the same time span, then:
Let’s denote time taken for both routes as 'T':
Therefore, D=36.5imesT.
Finding the difference:
Overall difference in distance between the two routes = |12000 - D|.
