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The floor plan of a house on sale in Johannesburg is shown on ANNEXURE A - NSC Mathematical Literacy - Question 3 - 2016 - Paper 1

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The floor plan of a house on sale in Johannesburg is shown on ANNEXURE A. Study the floor plan and the information given to answer the questions that follow. 1' = 3... show full transcript

Worked Solution & Example Answer:The floor plan of a house on sale in Johannesburg is shown on ANNEXURE A - NSC Mathematical Literacy - Question 3 - 2016 - Paper 1

Step 1

3.1. Determine the total number of doors that can be seen on the floor plan.

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Answer

To find the total number of doors, I examined the floor plan for visible doors. Upon review, I identified a total of 18 doors, which excludes any wardrobe doors.

Step 2

3.1.2. Give the general direction of the bedroom measuring 11" x 10"4 from the porch.

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Answer

The bedroom measuring 11" x 10"4 is located in the North West direction from the porch.

Step 3

3.1.3. Calculate the dimensions of the bedroom measuring 11" x 10"8 in metres.

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Answer

To convert inches to metres, I used the conversion factor of 1" = 0.0254 m.

The dimensions in inches are:

  • Length: 11" = 11 × 0.0254 = 0.2794 m
  • Width: 10"8 = 10 × 0.0254 + 8 × 0.0254 / 12 = 0.254 + 0.170 = 0.424 m

Thus, the dimensions in metres are approximately 0.2794 m by 0.424 m.

Step 4

3.1.4. Determine the scale used in the form of 1 : ...

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Answer

Using the scale provided, 1.5 cm on the floor plan represents 3,375 m in reality. This can be set up as:

Scale = 1.5 cm / 3,375 m = 1 / (3,375/1.5) = 1 : 2,250.

Thus, the scale is 1 : 2,250.

Step 5

3.2.1. Write down the departure time from East London and arrival time in Johannesburg.

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Answer

Mr. Dan departed from East London at 09:00 on Friday. He arrived in Johannesburg at 11:15 am on Saturday.

Step 6

3.2.2. Identify the station where Shosholoza-Meyl train stopped for the longest duration.

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Answer

The train stopped for the longest duration at Burgersdorp station.

Step 7

3.2.3. Calculate the average speed of the journey (East London–Johannesburg).

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Answer

The total journey time was 3 hours and 33 minutes, which is equivalent to 3 + 33/60 = 3.55 hours.

Distance from East London to Johannesburg is 992 km.

Average speed can be calculated using the formula:

Average speed = total distance / total time = 992 km / 3.55 hr ≈ 279.4 km/h.

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