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Thabo bakes round biscuits known as-Rb for sale - NSC Mathematical Literacy - Question 2 - 2016 - Paper 1

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Thabo bakes round biscuits known as-Rb for sale. He packs the biscuits in a cylindrical container made up of cardboard material. The diagram below shows the containe... show full transcript

Worked Solution & Example Answer:Thabo bakes round biscuits known as-Rb for sale - NSC Mathematical Literacy - Question 2 - 2016 - Paper 1

Step 1

2.1.1 Calculate the total surface area of the cardboard package required to make one cylindrical container.

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Answer

To find the total surface area of the cylindrical container, we use the formula:

A=2πr2+2πrlA = 2\pi r^2 + 2\pi r l

First, we need to find the radius (rr) from the diameter (d=90mmd = 90 \, mm):

r=d2=902=45mmr = \frac{d}{2} = \frac{90}{2} = 45 \, mm

Now we can substitute the values into the formula:

A=23.142(45)2+23.14245270A = 2 \cdot 3.142 \cdot (45)^2 + 2 \cdot 3.142 \cdot 45 \cdot 270

Calculating:

  • πr2=3.1422025=6362.85\pi r^2 = 3.142 \cdot 2025 = 6362.85,
  • 2πr2=26362.85=12725.72\pi r^2 = 2 \cdot 6362.85 = 12725.7,
  • 23.14245270=24377.632 \cdot 3.142 \cdot 45 \cdot 270 = 24377.63.

Thus, the total surface area is:

A=12725.7+24377.63=37103.33mm2A = 12725.7 + 24377.63 = 37103.33 \, mm^2

Step 2

2.1.2 Work out the area of the rectangular cardboard in mm².

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Answer

The area (AA) of the rectangular cardboard can be calculated using the formula:

A=width×lengthA = \text{width} \times \text{length}

Using the given dimensions:

  • Width = 120 cm = 1200 mm,
  • Length = 60 cm = 600 mm.

Thus:

A=1200mm×600mm=720000mm2A = 1200 \, mm \times 600 \, mm = 720000 \, mm^2

Step 3

2.1.3 Use your answers in QUESTIONS 2.1.1 and 2.1.2 to determine the number of cylindrical containers that can be made from one piece of cardboard.

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Answer

Now, to find the number of cylindrical containers (NN) that can be made, we use:

N=Area of the cardboardTotal surface area of one containerN = \frac{\text{Area of the cardboard}}{\text{Total surface area of one container}}

Substituting the areas calculated:

N=720000mm237103.33mm219.4319N = \frac{720000 \, mm^2}{37103.33 \, mm^2} \approx 19.43 \Rightarrow 19

Therefore, 19 cylindrical containers can be made.

Step 4

2.2.1 Calculate the number of drops of water that filled a litre container.

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Answer

Using the formula for the number of drops:

Number of drops=60sec×60min×1hourrate of the drops\text{Number of drops} = \frac{60\text{sec} \times 60\text{min} \times 1\text{hour}}{\text{rate of the drops}}

With a rate of one drop every 2 seconds, the calculation proceeds as follows:

Total time in seconds for one hour=3600sec\text{Total time in seconds for one hour} = 3600 \text{sec}

Now substituting:

Number of drops=3600sec2sec/drop=1800drops\text{Number of drops} = \frac{3600 \text{sec}}{2 \text{sec/drop}} = 1800 \text{drops}

Step 5

2.2.2 Calculate the volume of one drop of water in microlitres.

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Answer

Since 1 litre (L) = 1,000,000 microlitres (µL), and we have:

  • Total drops in 1 litre from the previous calculation = 1800 drops,

Therefore, the volume of one drop is:

Volume of one drop=1000000µL1800555.56µL\text{Volume of one drop} = \frac{1000000 \, µL}{1800} \approx 555.56 \, µL

Step 6

2.2.3 Work out the amount of water wasted from 01/01/2016 to 31/05/2016.

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Answer

To calculate the total water wasted:

  1. Determine the number of days from 01/01/2016 to 31/05/2016:

    • January: 31, February: 29, March: 31, April: 30, May: 31 = 31 + 29 + 31 + 30 + 31 = 152 days.
  2. Each day has 24 hours, hence:

    • Total hours = 152 days × 24 hours/day = 3648 hours.
  3. Each hour wastes 1 L, resulting in:

    • Total water wasted = 3648 L.

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