Tumi received a bursary to study at the University of Victoria in Canada - NSC Mathematical Literacy - Question 2 - 2021 - Paper 2

From the summary, Tumi continued onto Fort Street after Cadboro Road. The distance she travelled on Fort Street can be derived as follows:

The total route via Cadboro Road and Pandora Avenue is 12 km (6.8 km). The distances travelled are 0.19 km (190 m) on Cedar Hill Cross Road, 3.2 km on Cadboro Road, and 2.1 km on Pandora Avenue. Therefore, the distance on Fort Street is:

$ext{Distance on Fort Street} = 6.8 ext{ km} - (0.19 ext{ km} + 3.2 ext{ km} + 2.1 ext{ km})$

Calculating this gives: $ext{Distance on Fort Street} = 6.8 ext{ km} - 5.49 ext{ km} = 1.31 ext{ km}$

After crossing Fort Street, Tumi made a slight right onto Pandora Avenue, covering the remaining distance of 2.1 km until her destination.

For the second route, travelling from the University of Victoria to Victoria Downtown via Shelburne, the speed was 36.5 km/h. If we denote the time taken for this route as $t$ hours, the distance can be calculated using:

$ext{Distance} = 36.5 ext{ km/h} imes t$

However, since we need the comparison, let’s say the total distance for the Cadboro and Pandora route is 6.8 km (or 6800 meters). The respective distance for the Shelburne route needs to be calculated in time, multiplying speed by time to find a comparable measurement in meters. The exact distance travelled via this route must be known to identify the precise difference.