Martha koop skooluniforms vir haar seun en dogter - NSC Mathematical Literacy - Question 1 - 2022 - Paper 1
Question 1
Martha koop skooluniforms vir haar seun en dogter. Sy vergelyk die pryse van drie verskillende winkels, soos in TABEL 1 hieronder getoon.
TABEL 1: KOSTE VAN SKOOLUN... show full transcript
Worked Solution & Example Answer:Martha koop skooluniforms vir haar seun en dogter - NSC Mathematical Literacy - Question 1 - 2022 - Paper 1
Step 1
Identifiseer die pryse wat in TABEL 1 gegee word numeries
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Answer
Die pryse in TABEL 1 vir die skoolitems is:
Wit hemp: R110,00
Grys romp: R163,00 vir 2 (of R81,50 elke)
Grys kortbroek: R186,00 (of R93,00 elke) vir 2
Grys skoolkouse: R40,50 vir 2 pakke (of R20,25 elke)
Wit skoolkouse: R85,00 vir 5 pakke (of R17,00 elke)
Skoolseun (meisies): R349,00
Skoolseun (seuns): R318,00
Step 2
Rangskik, in stygende volgorde, die pryse wat in Winkel B gegee is
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Die pryse in Winkel B, in stygende volgorde, is:
Wit skoolkouse: R11,99 per pak
Grys kortbroek: R54,99
Grys romp: R54,99 vir 2 (of R27,49 elke)
Wit hemp: R44,99 elk
Skoolseun (meisies): R159,99
Skoolseun (seuns): R169,99
Step 3
Bereken die prys vir 'n pak wit skoolkouse by Winkel C
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Die prys vir 'n pak wit skoolkouse by Winkel C is R85,99 vir 5 pakke, wat neerkom op:
rac{R85,99}{5} = R17,20
per pak.
Step 4
Bepaal die ontbrekende waarde P, indien Martha al die skoolitems koop soos by Winkel A gegee.
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Die totale koste vir al die skoolitems aankoop by Winkel A is:
Wit hemp: R110,00
Grys romp: R163,00
Grys kortbroek: R186,00
Grys skoolkouse: R40,50
Wit skoolkouse: R85,00
Skoolseun (meisies): R349,00
Skoolseun (seuns): R318,00
Total cost (P):
P=110+163+186+40,50+85+349+318=R1251,50
Step 5
Definieer die term waarskynlikheid in die gegee konteks
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Answer
Waarskynlikheid verwys na die kans of moontlikheid dat 'n spesifieke gebeurtenis sal plaasvind. In hierdie konteks, dit is die kans dat Winkel C gekies word om al die skoolitems te koop.
Step 6
Skryf hierdie waarskynlikheid neer as 'n persentasie tot die naaste heelgetal af
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Answer
Die waarskynlikheid dat Winkel C gekies word is 0,3333333333. As 'n persentasie is dit:
0,3333333333 imes 100 = 33 ext{%}
so 'n afgeronde heelgetal is 33%.