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Parents Pricing Home NSC Mathematical Literacy Summarising data Definitions of some mathematical concepts are listed in TABLE 1 below
Definitions of some mathematical concepts are listed in TABLE 1 below - NSC Mathematical Literacy - Question 1 - 2017 - Paper 1 Question 1
View full question Definitions of some mathematical concepts are listed in TABLE 1 below.
TABLE 1: DEFINITIONS OF SOME MATHEMATICAL CONCEPTS
LETTER DEFINITIONS
A M... show full transcript
View marking scheme Worked Solution & Example Answer:Definitions of some mathematical concepts are listed in TABLE 1 below - NSC Mathematical Literacy - Question 1 - 2017 - Paper 1
Profit Only available for registered users.
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To calculate the profit made from the gold coin:
Profit can be determined by the formula:
e x t P r o f i t = e x t S e l l i n g P r i c e − e x t C o s t P r i c e ext{Profit} = ext{Selling Price} - ext{Cost Price} e x t P ro f i t = e x t S e ll in g P r i ce − e x t C os tP r i ce Where:
Selling Price = R18 700
Cost Price = R14 960
Thus,
e x t P r o f i t = R 18700 − R 14960 = R 3740 ext{Profit} = R18 700 - R14 960 = R3 740 e x t P ro f i t = R 18700 − R 14960 = R 3740
Mean Only available for registered users.
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The mean is defined as the average value of a given data set, calculated as:
ext{Mean} = rac{ ext{Sum of all values}}{ ext{Number of values}}
Thus, for our purposes, the mean is represented by letter G in the definition table.
Length of the radius Only available for registered users.
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The radius of a circle can be calculated using the diameter. Given the diameter of the gold coin is 32.8 mm:
The formula for the radius is:
ext{Radius} = rac{ ext{Diameter}}{2} = rac{32.8 ext{ mm}}{2} = 16.4 ext{ mm}
Calculate the profit that the shop made on the one-ounce gold coin. Only available for registered users.
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The profit calculated previously is R3 740.
Determine the exact time when the coin was sold. Only available for registered users.
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The shop bought the coin at 10:15 and sold it 5 hours and 50 minutes later. To determine the selling time, add:
10 : 15 + 5 : 50 = 16 : 05 e x t o r 4 : 05 e x t P M 10:15 + 5:50 = 16:05 ext{ or } 4:05 ext{ PM} 10 : 15 + 5 : 50 = 16 : 05 e x t or 4 : 05 e x t PM
Calculate the length of the radius of the coin. Only available for registered users.
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As calculated, the radius of the coin is 16.4 mm.
Determine the shortest distance (D) between the edge of the coin and the side of the square box. Only available for registered users.
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To find the shortest distance (D), we need to consider the side length of the square box and the radius of the coin:
The side length of the square box is 71.8 mm.
Thus, the shortest distance D will be calculated as:
D = e x t S i d e l e n g t h o f b o x − e x t D i a m e t e r o f c o i n = 71.8 e x t m m − 32.8 e x t m m = 39.0 e x t m m D = ext{Side length of box} - ext{Diameter of coin} = 71.8 ext{ mm} - 32.8 ext{ mm} = 39.0 ext{ mm} D = e x t S i d e l e n g t h o f b o x − e x t D iam e t ero f co in = 71.8 e x t mm − 32.8 e x t mm = 39.0 e x t mm
Calculate the cost per litre of the diluted juice. Only available for registered users.
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The total cost of the diluted juice is R44.95 for 14 ℓ of diluted juice. To find the cost per litre:
ext{Cost per litre} = rac{44.95}{14} ext{ R} ext{ which approximately evaluates to R3.21}
Determine, in simplified form, the ratio of volume of diluted juice : volume of water. Only available for registered users.
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The volume of diluted juice is 14 ℓ and the volume of water added is:
e x t W a t e r V o l u m e = 14 ℓ − 2 ℓ = 12 ℓ ext{Water Volume} = 14 ℓ - 2 ℓ = 12 ℓ e x t Wa t er V o l u m e = 14 ℓ − 2 ℓ = 12 ℓ Thus, the simplified ratio is:
e x t R a t i o = 14 : 12 = 7 : 6 ext{Ratio} = 14 : 12 = 7 : 6 e x t R a t i o = 14 : 12 = 7 : 6
Determine the exact number of glasses of diluted juice that can be served. Only available for registered users.
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Each glass contains 0.175 ℓ of diluted juice. Therefore, the number of glasses can be calculated as:
ext{Number of glasses} = rac{14}{0.175} = 80 ext{ glasses}
Arrange the mean monthly rainfall for Durban in ascending order. Only available for registered users.
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The mean monthly rainfall for Durban in ascending order is:
April: 39 mm
May: 39 mm
June: 35 mm
July: 63 mm
August: 64 mm
September: 107 mm
October: 127 mm
November: 75 mm
December: 86 mm
January: 126 mm
February: 127 mm
March: 120 mm
In which month does Kimberley receive the lowest mean monthly rainfall? Only available for registered users.
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Kimberley receives the lowest mean monthly rainfall in April, with 0 mm.
Write down the modal number of rainy days for the first six months of the year for Durban. Only available for registered users.
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The modal number of rainy days for Durban in the first six months is 10 rainy days (found in both January and June).
In which month does Kimberley have a higher mean monthly rainfall than Durban? Only available for registered users.
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Kimberley has higher mean monthly rainfall than Durban in January and February.
During which month(s) is the mean monthly rainfall in Durban the same? Only available for registered users.
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The mean monthly rainfall in Durban is the same in May and June, both with 39 mm.
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