SimpleStudy Schools Book a Demo We can give expert advice on our plans and what will be the best option for your school.
Parents Pricing Home NSC Mathematical Literacy Using a calculator Excessive sugar intake is a health hazard
Excessive sugar intake is a health hazard - NSC Mathematical Literacy - Question 3 - 2017 - Paper 1 Question 3
View full question Excessive sugar intake is a health hazard. Study the information about the amount of sugar in the chosen items mentioned in TABLE 4 below and answer the questions th... show full transcript
View marking scheme Worked Solution & Example Answer:Excessive sugar intake is a health hazard - NSC Mathematical Literacy - Question 3 - 2017 - Paper 1
Rose drinks a can of ice tea and eats two medium muffins for breakfast, one chocolate bar at break and one sports drink in the afternoon. Calculate Rose’s total amount of sugar intake. Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
To calculate the total amount of sugar intake, we can use the following values:
Ice tea: 15 g
Medium muffin: 10.6 g (2 muffins: 2 i m e s 10.6 = 21.2 2 imes 10.6 = 21.2 2 im es 10.6 = 21.2
Chocolate bar: 4.2 g
Sports drink: 28 g
Now, sum these values:
e x t T o t a l S u g a r I n t a k e = 15 + 21.2 + 4.2 + 28 = 68.4 e x t g ext{Total Sugar Intake} = 15 + 21.2 + 4.2 + 28 = 68.4 ext{ g} e x t T o t a lS ug a r I n t ak e = 15 + 21.2 + 4.2 + 28 = 68.4 e x t g
Determine the number of teaspoons of sugar in the vitamin water drink. Round your answer to the nearest teaspoon. Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
The sugar content in vitamin water is 2.75 g. To convert grams to teaspoons, use the conversion factor (1 teaspoon = 4.18 g):
ightarrow 0.66 ext{ teaspoons} \\ ext{Rounded}
ightarrow 1 ext{ teaspoon}$$
Calculate the number of cups you will get when you buy 50 bottles of sports drink for your school teams. Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Each bottle of sports drink has a capacity of 500 mℓ. Therefore, the total volume from 50 bottles is:
e x t T o t a l V o l u m e = 50 i m e s 500 e x t m ℓ = 25000 e x t m ℓ ext{Total Volume} = 50 imes 500 ext{ mℓ} = 25000 ext{ mℓ} e x t T o t a l V o l u m e = 50 im es 500 e x t m ℓ = 25000 e x t m ℓ
Since 1 cup = 250 mℓ, the number of cups can be calculated as:
ext{Number of Cups} = rac{25000}{250} = 100 ext{ cups}
Calculate the volume of the box. Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
To calculate the volume of the box, we can apply the formula:
e x t V o l u m e = e x t l e n g t h i m e s e x t w i d t h i m e s e x t h e i g h t = 28 e x t c m i m e s 15 e x t c m i m e s 8 e x t c m = 3360 e x t c m 3 ext{Volume} = ext{length} imes ext{width} imes ext{height} = 28 ext{ cm} imes 15 ext{ cm} imes 8 ext{ cm} = 3360 ext{ cm}^3 e x t V o l u m e = e x t l e n g t h im ese x t w i d t h im ese x t h e i g h t = 28 e x t c m im es 15 e x t c m im es 8 e x t c m = 3360 e x t c m 3
Determine the thickness of a chocolate if the area of its base is 35 cm². Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Using the formula for volume:
e x t V o l u m e = e x t a r e a o f b a s e i m e s e x t t h i c k n e s s , ext{Volume} = ext{area of base} imes ext{thickness}, e x t V o l u m e = e x t a re a o f ba se im ese x t t hi c kn ess ,
where we know the volume of one chocolate bar is:
360 e x t c m 3 = 35 e x t c m 2 i m e s e x t t h i c k n e s s 360 ext{ cm}^3 = 35 ext{ cm}^2 imes ext{thickness} 360 e x t c m 3 = 35 e x t c m 2 im ese x t t hi c kn ess
Now solve for thickness:
ightarrow ext{Approximately } 10.29 ext{ cm}$$
Calculate the diameter of the tablecloth to be cut from the material, including the additional centimeters for the hem. Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
To find the diameter of the tablecloth, we must add the diameter of the table to the overhang:
e x t D i a m e t e r = 130 e x t c m + 2 i m e s 25 e x t c m = 130 e x t c m + 50 e x t c m = 180 e x t c m ext{Diameter} = 130 ext{ cm} + 2 imes 25 ext{ cm} = 130 ext{ cm} + 50 ext{ cm} = 180 ext{ cm} e x t D iam e t er = 130 e x t c m + 2 im es 25 e x t c m = 130 e x t c m + 50 e x t c m = 180 e x t c m
Calculate the area (in m²) of the tablecloth material. Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Using the formula for area:
e x t A r e a = e x t L e n g t h i m e s e x t B r e a d t h = 2.3 e x t m i m e s 2.3 e x t m = 5.29 e x t m 2 ext{Area} = ext{Length} imes ext{Breadth} = 2.3 ext{ m} imes 2.3 ext{ m} = 5.29 ext{ m}^2 e x t A re a = e x t L e n g t h im ese x t B re a d t h = 2.3 e x t m im es 2.3 e x t m = 5.29 e x t m 2
Calculate the area (in m²) of a tablecloth to be cut by Lindi. Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Using the formula:
e x t A r e a = e x t π i m e s ( e x t r a d i u s ) 2 ext{Area} = ext{π} imes ( ext{radius})^2 e x t A re a = e x t π im es ( e x t r a d i u s ) 2
First, find the radius:
ext{Radius} = rac{180}{2} = 90 ext{ cm} = 0.9 ext{ m}
Now calculate the area:
e x t A r e a = 3.142 i m e s ( 0.9 ) 2 = 3.142 i m e s 0.81 = 2.54 e x t m 2 ext{Area} = 3.142 imes (0.9)^2 = 3.142 imes 0.81 = 2.54 ext{ m}^2 e x t A re a = 3.142 im es ( 0.9 ) 2 = 3.142 im es 0.81 = 2.54 e x t m 2
Calculate the amount of material wasted when cutting the table cloth. Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Using the formula for wasted material:
e x t W a s t e d m a t e r i a l = e x t A r e a o f m a t e r i a l − e x t A r e a o f t a b l e c l o t h = 5.29 e x t m 2 − 2.54 e x t m 2 = 2.75 e x t m 2 ext{Wasted material} = ext{Area of material} - ext{Area of tablecloth} = 5.29 ext{ m}^2 - 2.54 ext{ m}^2 = 2.75 ext{ m}^2 e x t Wa s t e d ma t er ia l = e x t A re a o f ma t er ia l − e x t A re a o f t ab l ec l o t h = 5.29 e x t m 2 − 2.54 e x t m 2 = 2.75 e x t m 2
Join the NSC students using SimpleStudy...97% of StudentsReport Improved Results
98% of StudentsRecommend to friends
100,000+ Students Supported
1 Million+ Questions answered
© 2025 SimpleStudy. All rights reserved
