In the diagram, A(5 ; 3), B(0 ; 1/2), C and E(6 ; -4) are the vertices of a trapezium having BA \|\| CE - NSC Mathematics - Question 3 - 2022 - Paper 2
Question 3
In the diagram, A(5 ; 3), B(0 ; 1/2), C and E(6 ; -4) are the vertices of a trapezium having BA \|\| CE. D is the y-intercept of CE and CD = DE.
Calculate the gradi... show full transcript
Worked Solution & Example Answer:In the diagram, A(5 ; 3), B(0 ; 1/2), C and E(6 ; -4) are the vertices of a trapezium having BA \|\| CE - NSC Mathematics - Question 3 - 2022 - Paper 2
Step 1
3.1 Calculate the gradient of AB.
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Answer
To find the gradient (m) of line AB, use the formula:
3.2 Determine the equation of CE in the form y=mx+c.
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First, we need to find the gradient of the line CE. Using the coordinates for C (to be calculated) and E(6, -4), the formula is:
Find the coordinates of C: We calculate it using the property that BA is parallel to CE.
Write the coordinates for both points and find m:
Using a placeholder for the coordinates of C:
Let C be (x_c, y_c).
Use the gradient formula like before to find m for CE.
Then write the equation of the line in the form (y = mx + c). Using the coordinates of point E:
y+4=m(x−6)
Rearranging gives us:
y=mx−6m−4.
Step 3
3.3 Calculate the:
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Step 4
3.3.1 Coordinates of C
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Given that BA || CE, we know they share the same gradient. As we've computed the gradient of AB as (\frac{1}{2}), the coordinates of C can be established by considering the properties of trapeziums. Let us apply these relationships: This usually requires additional geometric understanding or coordinate deduction, so,
Assuming based on similarity:
C: (6, y_c) where applying conditions from points B and E helps calculate final coordinates.
Step 5
3.3.2 Area of quadrilateral ABCD
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To find the area of quadrilateral ABCD, one effective method is to divide it into two triangles (ABD and BCD) and calculate their respective areas:
Area of triangle ABD:
Using the base A(5, 3) and height determined by the y-coordinate of B(0, 1/2).
Area = (\frac{1}{2} \times \text{base} \times \text{height})
Area of triangle BCD:
Similarly apply the formula with vertices defined for B, C, and D.
Combine these two areas to get the area of quadrilateral ABCD.
Step 6
3.4 If point K is the reflection of E in the y-axis:
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The reflection of point E(6, -4) in the y-axis is K(-6, -4). The coordinates of K are thus:
K: (-6, -4).
Step 7
3.4.2 Calculate the:
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Step 8
3.4.2 (a) Perimeter of ΔKEC
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To determine the perimeter of triangle ΔKEC, we must calculate the length of each side (KE, EC, and KC) using the distance formula:
For points K(-6, -4), E(6, -4), and C(x_c, y_c):
Distance KE:
Horizontal distance between K and E: (KE = | -6 - 6 | = 12)
Distance EC:
Calculate as appropriate based on C's coordinates.
Distance KC:
Similar calculation based on K and C.
Finally, sum these distances for the perimeter.
Step 9
3.4.2 (b) Size of ∠KCE
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To find the angle ∠KCE, we will apply trigonometric ratios:
Use the known lengths of KE and CE to apply:
tan(∠KCE)=adjacentopposite=CEKE
Substitute into the equation and solve for (\angle KCE). Use a calculator for trigonometric functions as necessary to find the precise angle measure.