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In the diagram, W is a point on the circle with centre O - NSC Mathematics - Question 10 - 2017 - Paper 2

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Question 10

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In the diagram, W is a point on the circle with centre O. V is a point on OW. Chord MN is drawn such that MV = VN. The tangent at W meets OM produced at T and ON pro... show full transcript

Worked Solution & Example Answer:In the diagram, W is a point on the circle with centre O - NSC Mathematics - Question 10 - 2017 - Paper 2

Step 1

10.1 Give a reason why OV ⊥ MN.

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Answer

The line from the centre O to the midpoint of the chord MN is perpendicular to the chord itself. Therefore, since V lies on this line, we have OV ⊥ MN.

Step 2

10.2.1 MN || TS

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Answer

To prove that MN || TS, we observe that the angles subtended by the same arc are equal. Therefore, we can establish that:

OWT=OMV\angle OWT = \angle OMV

Since these angles are equal, by the corresponding angles criterion, we conclude that MN || TS.

Step 3

10.2.2 TMNS is a cyclic quadrilateral

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Answer

To prove that TMNS is a cyclic quadrilateral, we need to show that the opposite angles are supplementary. We can ascertain:

MTS+MNS=180\angle MTS + \angle MNS = 180^\circ

This is derived from the fact that angles subtended by the same chord are equal, which fulfills the requirement for TMNS being a cyclic quadrilateral.

Step 4

10.2.3 OS ⋅ MN = 2ON ⋅ WS

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Answer

To prove the relationship between OS, MN, ON, and WS:

  1. We first establish that OV = VN, as given in the problem statement.
  2. Then, since we have the angles in triangles AOV and AOW equal, we can use similarity: OSON=WSVN\frac{OS}{ON} = \frac{WS}{VN}.
  3. Applying the property of similar triangles, we can multiply both sides by ON and substitute to derive the equation:
    OSMN=2ONWSOS \cdot MN = 2ON \cdot WS.

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