Vraag 8.1
In die diagram hieronder is raakyln KT aan die sirkel by K ewewydig aan die koord NM - NSC Mathematics - Question 8 - 2016 - Paper 2
Question 8
Vraag 8.1
In die diagram hieronder is raakyln KT aan die sirkel by K ewewydig aan die koord NM. NT sny die sirkel by L. ∠AKML is getrek. M₂ = 40° en MKT = 84°.
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Worked Solution & Example Answer:Vraag 8.1
In die diagram hieronder is raakyln KT aan die sirkel by K ewewydig aan die koord NM - NSC Mathematics - Question 8 - 2016 - Paper 2
Step 1
8.1.1 K₂
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Answer
K₂ = M₂ = 40°
Toepas die tan koordstelling.
Step 2
8.1.2 N₁
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Answer
N₁ = K₂
∠s in dies segm = 84° - 40° = 44°.
Step 3
8.1.3 T₁
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Answer
T₁ = N₁ = 44°
Toepas die alternatiewe hoeke.
Step 4
8.1.4 L₂
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Answer
L₂ = K₂ + T₁
L₂ = 40° + 44° = 84°.
Step 5
8.1.5 L₁
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Answer
In ΔKLM:
44° + 84° + 40° + L₁ = 180°
∠s sum in Δ.
Step 6
8.2
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