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Question 10
EHGF is a rectangle. HE is produced $x^2$ cm to N and EH is produced $x^2$ cm to P. NF produced intersects PG produced at M to form an isosceles triangle MNP with NM... show full transcript
Step 1
Answer
To find the area of rectangle EFHG, we first identify the lengths of sides NE and EH. From the diagram, we can see that:
The ratio of NE to EF is given by:
Hence, we can express EF as:
Given EH = 4 - 2 * NE, we have:
The area A of the rectangle EFHG can now be calculated by:
After simplifying, we will derive:
Step 2
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