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7.1 How many years will it take for an investment to double in value, if it earns interest at a rate of 8,5% p.a., compounded quarterly? 7.2 A company purchased machinery for R500 000 - NSC Mathematics - Question 7 - 2022 - Paper 1

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7.1-How-many-years-will-it-take-for-an-investment-to-double-in-value,-if-it-earns-interest-at-a-rate-of-8,5%-p.a.,-compounded-quarterly?--7.2-A-company-purchased-machinery-for-R500-000-NSC Mathematics-Question 7-2022-Paper 1.png

7.1 How many years will it take for an investment to double in value, if it earns interest at a rate of 8,5% p.a., compounded quarterly? 7.2 A company purchased mac... show full transcript

Worked Solution & Example Answer:7.1 How many years will it take for an investment to double in value, if it earns interest at a rate of 8,5% p.a., compounded quarterly? 7.2 A company purchased machinery for R500 000 - NSC Mathematics - Question 7 - 2022 - Paper 1

Step 1

How many years will it take for an investment to double in value, if it earns interest at a rate of 8,5% p.a., compounded quarterly?

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Answer

To determine the number of years required for an investment to double in value, we use the compound interest formula:

A=P(1+i)nA = P(1 + i)^n

Where:

  • AA is the amount of money accumulated after n years, including interest.
  • PP is the principal amount (initial investment).
  • ii is the interest rate per period.
  • nn is the number of periods.

Setting A=2PA = 2P, we have:

2P=P(1+0.085/4)4n2P = P(1 + 0.085/4)^{4n}

This simplifies to:

2=(1+0.02125)4n2 = (1 + 0.02125)^{4n}

Taking log on both sides:

4n = rac{ ext{log}(2)}{ ext{log}(1 + 0.02125)}

From calculations, we find:

n=8.24extyearsn = 8.24 ext{ years}

Step 2

Calculate the rate of depreciation of the old machinery over the 5 years, using the reducing-balance method.

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Answer

Using the reducing-balance method, we start with:

R180,000=R500,000(1r)5R180,000 = R500,000(1 - r)^5

Where:

  • R180,000R180,000 is the salvage value after 5 years.
  • R500,000R500,000 is the original value.
  • rr is the depreciation rate.

This gives us:

(1 - r)^5 = rac{R180,000}{R500,000}

Taking the fifth root:

1 - r = rac{R180,000^{1/5}}{R500,000^{1/5}}

Calculating this, we find the depreciation rate rextasapproximately18.48%r ext{ as approximately } 18.48\%.

Step 3

The rate of inflation for the cost of the new machinery is 6,3% p.a. over the 5 years. What will the new machinery cost at the end of 5 years?

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Answer

We can calculate the future value of the new machinery using the compound interest formula again:

A=P(1+i)nA = P(1 + i)^n

Given:

  • P=R500,000+0.063/R500,000P = R500,000 + 0.063/R500,000 (adding the inflation component)
  • i=0.063i = 0.063 (6.3% inflation rate)
  • n=5n = 5 (number of years)
  • Finally, we get AR678,635.11A \approx R678,635.11.

Step 4

The company set up a sinking fund and made the first payment into this fund on the day the old machinery was bought. The last payment was made three months before the new machinery was purchased at the end of the 5 years. Calculate the monthly payment into the sinking fund.

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Answer

To find the monthly payment into the sinking fund, we use:

S=R498,635.11S = R498,635.11

Where SS is the value of the sinking fund. To calculate the monthly payment:

  • Interest rate i = rac{10.25\%}{12} = 0.00854167
  • Time t=58t = 58 months

The formula for the sinking fund is:

R = rac{S imes i}{(1+i)^t - 1}

Solving gives:

R=R6,510.36R = R6,510.36

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