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Given the function $f(x) = x^2 - 2x - 24$: 1 - NSC Mathematics - Question 7 - 2021 - Paper 1

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Given the function $f(x) = x^2 - 2x - 24$: 1. Find the x-coordinate of the vertex. 2. Determine the y-coordinate of the vertex. 3. Give the coordinates of the verte... show full transcript

Worked Solution & Example Answer:Given the function $f(x) = x^2 - 2x - 24$: 1 - NSC Mathematics - Question 7 - 2021 - Paper 1

Step 1

Find the x-coordinate of the vertex:

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Answer

To find the x-coordinate of the vertex for the quadratic function in the form f(x)=ax2+bx+cf(x) = ax^2 + bx + c, we use the formula:

x=b2ax = -\frac{b}{2a}

For the function f(x)=x22x24f(x) = x^2 - 2x - 24, we have:

  • a=1a = 1
  • b=2b = -2

Substituting these values, we calculate:

x=22(1)=22=1x = -\frac{-2}{2(1)} = \frac{2}{2} = 1

Step 2

Determine the y-coordinate of the vertex:

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Answer

Next, we substitute x=1x = 1 back into the function to find the y-coordinate:

y=f(1)=(1)22(1)24=1224=25y = f(1) = (1)^2 - 2(1) - 24 = 1 - 2 - 24 = -25

Step 3

Give the coordinates of the vertex:

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Answer

The coordinates of the vertex are therefore (1,25)(1, -25). Thus, the final answer is:

C(1,25)C(1, -25)

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