Given the geometric series:
\( \frac{1}{5} + \frac{1}{15} + \frac{1}{45} + \ldots \)
2.1.1 Is this a convergent geometric series? Justify your answer with the necessary calculations - NSC Mathematics - Question 2 - 2023 - Paper 1
Question 2
Given the geometric series:
\( \frac{1}{5} + \frac{1}{15} + \frac{1}{45} + \ldots \)
2.1.1 Is this a convergent geometric series? Justify your answer with the nece... show full transcript
Worked Solution & Example Answer:Given the geometric series:
\( \frac{1}{5} + \frac{1}{15} + \frac{1}{45} + \ldots \)
2.1.1 Is this a convergent geometric series? Justify your answer with the necessary calculations - NSC Mathematics - Question 2 - 2023 - Paper 1
Step 1
2.1.1 Is this a convergent geometric series? Justify your answer with the necessary calculations.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To determine if the series is convergent, we need to find the common ratio ( r ). The first term is ( a = \frac{1}{5} ) and the second term is ( \frac{1}{15} ). The common ratio can be calculated as follows:
2.2.1 Write down the next TWO terms of the pattern.
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The pattern of the sequence alternates between arithmetic and geometric components. Following the existing terms:
( P_0 = \frac{1}{3}, P_1 = 2, P_2 = 2 \cdots, P_3 = \frac{1}{27} ), we can find the next two terms:
The next term after ( P_3 ) should continue the arithmetic part, resulting in ( P_4 = \frac{4}{3} )
The term after that in the geometric sequence gives ( P_5 = \frac{2}{81} ).
Step 4
2.2.2 Determine the general term t_n for the odd terms of this pattern. Write down your answer in terms of x.
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The odd terms of the sequence can be represented in general as follows:
[ t_n = x + (n - 1) \cdot x ]
This means every odd term can be expressed in terms of ( x ) where ( n ) is the term index.
Step 5
2.2.3 Calculate the value of P_{26}.
97%
117 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To find ( P_{26} ), we observe that it is an even-indexed term. Thus, using the geometric pattern we established:
[ P_{26} = \frac{1}{3} \cdot \left( \frac{1}{3} \right)^{25} = \frac{1}{3^{26}} = \frac{1}{1594323} ].
Step 6
2.2.4 If \( \sum_{n=1}^{21} P_n = 33.5 \), determine the value of x.
97%
121 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To find the value of ( x ), we set up the equation using the sum of the arithmetic and geometric series:
[ S = S_1 + S_0 = \frac{11}{2}(2x + 10) ]
This simplifies into the equation:
[ 33.5 = 66 + 0.5 ]
Solving for ( x ) yields ( x = 2.5 )