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Die mate van sukses van die Fana-sokkerspan hang van 'n aantal verskillende faktore af - NSC Mathematics - Question 11 - 2017 - Paper 1

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Die mate van sukses van die Fana-sokkerspan hang van 'n aantal verskillende faktore af. Die fiksheid van die spelers is een van die faktore wat die uitslag van 'n we... show full transcript

Worked Solution & Example Answer:Die mate van sukses van die Fana-sokkerspan hang van 'n aantal verskillende faktore af - NSC Mathematics - Question 11 - 2017 - Paper 1

Step 1

Calculate P(F and W)

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Answer

To find the probability that the team wins given that all the players are fit:

  • The probability that all the players are fit is given as P(F)=0.7P(F) = 0.7.
  • If all the players are fit, the probability of winning the next match is P(WF)=0.85P(W|F) = 0.85. Thus:

P(F and W)=P(F)×P(WF)=0.7×0.85=0.595P(F \text{ and } W) = P(F) \times P(W|F) = 0.7 \times 0.85 = 0.595

Step 2

Calculate P(not F and W)

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Answer

Next, we calculate the probability that not all players are fit and they still win:

  • The probability that not all the players are fit is P(notF)=0.3P(not F) = 0.3.
  • The probability of winning given that not all players are fit is P(WnotF)=0.45P(W|not F) = 0.45. Thus:

P(notF and W)=P(notF)×P(WnotF)=0.3×0.45=0.135P(not F \text{ and } W) = P(not F) \times P(W|not F) = 0.3 \times 0.45 = 0.135

Step 3

Calculate Total Probability of Winning

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Answer

Finally, we use the law of total probability to find the overall chance of winning:

P(Win)=P(F and W)+P(notF and W)P(Win) = P(F \text{ and } W) + P(not F \text{ and } W)

Substituting the calculated values:

P(Win)=0.595+0.135=0.76P(Win) = 0.595 + 0.135 = 0.76

Therefore, the overall probability that the Fana-sokkerspan wins the next match is 76%.

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