A bakery kept a record of the number of loaves of bread a tuck-shop ordered daily over the last 18 days - NSC Mathematics - Question 1 - 2021 - Paper 2
Question 1
A bakery kept a record of the number of loaves of bread a tuck-shop ordered daily over the last 18 days. The information is shown in the table below
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Worked Solution & Example Answer:A bakery kept a record of the number of loaves of bread a tuck-shop ordered daily over the last 18 days - NSC Mathematics - Question 1 - 2021 - Paper 2
Step 1
1.1.1 Mean number of loaves of bread ordered daily
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Answer
To find the mean number of loaves ordered daily, we sum the total number of loaves for the 18 days:
396=10+11+13+14+15+16+18+18+19+20+21+35+37+40+41
Then we divide this total by the number of days:
xˉ=18396=22
Thus, the mean number of loaves ordered daily is 22.
Step 2
1.1.2 Standard deviation of the data
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Answer
The standard deviation (σ) is calculated as follows:
Calculate the variance by finding the squared differences from the mean and averaging them:
σ≈10.1707extthen,σ≈10.17
Thus, the standard deviation of the data is 10.17.
Step 3
1.1.3 Number of days on which the number of loaves of bread ordered was more than one standard deviation above the mean
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Answer
The mean is 22 and one standard deviation above the mean is:
xˉ+σ=22+10.17=32.17
Next, we check how many days ordered more than 32.17 loaves:
Days with orders: 35, 37, 40, 41
This gives us 4 days.
Step 4
1.2 Calculate the number of loaves of bread which were NOT sold over the 18 days
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Answer
The total ordered is 396 loaves and the total sold over 18 days is:
20×18=360
Thus, the number of loaves not sold is:
396−360=36
So, the number of loaves of bread which were NOT sold is 36.
Step 5
1.3.1 Which ONE of the two box and whisker diagrams represents the data?
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Answer
Graph B is correct.
Reason: The median (18.5), first quartile (Q1 = 14), and third quartile (Q3 = 21) align with the values derived from the data.
Step 6
1.3.2 Describe the skewness of the data.
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Answer
The data is positively skewed.
This indicates that the mean is greater than the median, as outliers on the right pull the tail longer.