The table below shows the size (in carats) and the price (in rands) of 10 diamonds that were sold by a diamond trader - NSC Mathematics - Question 2 - 2022 - Paper 2
Question 2
The table below shows the size (in carats) and the price (in rands) of 10 diamonds that were sold by a diamond trader. This information is also presented in the scat... show full transcript
Worked Solution & Example Answer:The table below shows the size (in carats) and the price (in rands) of 10 diamonds that were sold by a diamond trader - NSC Mathematics - Question 2 - 2022 - Paper 2
Step 1
Determine the equation of the least squares regression line for the data.
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Answer
To find the least squares regression line, we need to calculate the slope (m) and the y-intercept (b) using the least squares formula. The linear regression formula is given by:
Substitute these values into the formulas for m and b to determine the equation.
This results in the least squares regression equation being:
y=mx+b
Step 2
If the trader sold a diamond that was 0.25 carats in size, predict the selling price of this diamond in rands.
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Answer
Once we have determined the values of m and b from the previous step, we can substitute x=0.25 into the regression equation:
y=m(0.25)+b
This will yield the predicted price of the diamond with a size of 0.25 carats.
Step 3
Calculate the average price increase per 0,05 carat of the diamonds.
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Answer
To find the average price increase per 0.05 carat, we can calculate the difference in price for a 0.05 carat increase. This can be done using the regression line equation based on the derived slope m:
Average Price Increase=m×0.05
Plug in the value of m to calculate the actual increase.
Step 4
Explain the reason for the change in correlation due to the price correction.
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The correction of the selling price of the 0.35 carat diamond to R11 500 impacts the overall data set and the least squares regression line. With accurate pricing, the data becomes less skewed, leading to a more linear relationship between size and price. The scatter plot will show points that are more closely aligned along the regression line after correcting this value, which reflects a stronger correlation. By reducing anomalies, the data set offers a clearer insight into the true relationship between diamond size and price.