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At a certain school, the staff committee wanted to determine how many glasses of water the staff members drank during a school day - NSC Mathematics - Question 2 - 2023 - Paper 2

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At a certain school, the staff committee wanted to determine how many glasses of water the staff members drank during a school day. All teachers present on a specifi... show full transcript

Worked Solution & Example Answer:At a certain school, the staff committee wanted to determine how many glasses of water the staff members drank during a school day - NSC Mathematics - Question 2 - 2023 - Paper 2

Step 1

Complete the cumulative frequency column provided in the table in the ANSWER BOOK.

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Answer

To complete the cumulative frequency table, add the number of staff members in each category:

  • For 0 ≤ x < 2: Cumulative frequency = 5
  • For 2 ≤ x < 4: Cumulative frequency = 5 + 15 = 20
  • For 4 ≤ x < 6: Cumulative frequency = 20 + 13 = 33
  • For 6 ≤ x < 8: Cumulative frequency = 33 + 5 = 38
  • For 8 ≤ x < 10: Cumulative frequency = 38 + 2 = 40

Complete table:

NUMBER OF GLASSES OF WATER DRANK PER DAY | CUMULATIVE FREQUENCY 0 ≤ x < 2 | 5 2 ≤ x < 4 | 20 4 ≤ x < 6 | 33 6 ≤ x < 8 | 38 8 ≤ x < 10 | 40

Step 2

How many staff members were interviewed?

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Answer

To find the total number of staff members that were interviewed, sum the number of staff members from all categories:

Total = 5 + 15 + 13 + 5 + 2 = 40 staff members.

Step 3

How many staff members drank fewer than 6 glasses of water during a school day?

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Answer

To find how many staff members drank fewer than 6 glasses of water, add the categories for 0 ≤ x < 2 and 2 ≤ x < 4 and 4 ≤ x < 6:

Number of staff members = 5 + 15 + 13 = 33 staff members drank fewer than 6 glasses of water.

Step 4

How many teachers were absent on the day of the interviews?

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Answer

Let the mean of the k absent teachers be expressed as:

ar{x} = \frac{(1 \times \frac{k}{2}) + (3 \times 15) + (5 \times (13 + \frac{k}{2})) + (7 \times 5) + (9 \times 2)}{40 + k} = 4

Substituting the values:

5+k2+45+65+35+18+4k=160+4k5 + \frac{k}{2} + 45 + 65 + 35 + 18 + 4k = 160 + 4k

Solving gives:

3k+1684k=0k=83k + 168 - 4k = 0 \Rightarrow k = 8

Thus, 8 teachers were absent on the day of the interviews.

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