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In die diagram is O die middelpunt van sirkel KLNM en KO en OM is verbind - NSC Mathematics - Question 8 - 2017 - Paper 2

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In die diagram is O die middelpunt van sirkel KLNM en KO en OM is verbind. Koord KN is verleng na S. $ ext{K}_2 = 55^ ext{o}$ en $ ext{N}_2 = 100^ ext{o}$. Bepaal,... show full transcript

Worked Solution & Example Answer:In die diagram is O die middelpunt van sirkel KLNM en KO en OM is verbind - NSC Mathematics - Question 8 - 2017 - Paper 2

Step 1

8.1 $ ext{L}^ ext{i}$

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Answer

Die hoeke in 'n sikliese kwadrant ( ext{cyclic quad}) is teenoor mekaar gelyk. Dus, Lexti=100extoL^ ext{i} = 100^ ext{o}.

Step 2

8.2 $ ext{O}^ ext{i}$

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Answer

Aangesien extN1 ext{N}_1 op 'n regstreekse lyn ( ext{straight line}) is, N1=80extoN_1 = 80^ ext{o}.

En omdat die middelpunt die sirkel se hoeke is, weet ons dat: O1=160extoO_1 = 160^ ext{o}.

Step 3

8.3 $ ext{M}^ ext{i}$

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Answer

Die som van die hoeke in die kwadrant is gelyk aan: Mi=360exto(100exto+55exto+160exto)M_i = 360^ ext{o} - (100^ ext{o} + 55^ ext{o} + 160^ ext{o})

Daarom is: Mi=45extoM_i = 45^ ext{o}.

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