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Question 6
Given $$f(x) = an \left( \frac{1}{2} x \right)$$ and $$g(x) = \sin \left( x - 30^{\circ} \right) \text{ for } x \in [-90^{\circ}; 180^{\circ}]$$ 6.1 On the sa... show full transcript
Step 1
Answer
To draw the graphs of the functions, we start with the graph of . The function has vertical asymptotes at the points where the tangent function is undefined, which occur at:
for integer values of . For our interval, the asymptotes occur at and . The graph will oscillate between these points, with turning points occurring within these intervals.
For the function , the graph will oscillate between -1 and 1, with a phase shift of . We can plot this on the same axes, showing how both functions intersect, their turning points, and the asymptotes for .
Step 2
Step 3
Answer
To find the values of for which , we analyze the signs of both functions over the interval .
Thus, the solution for when occurs in:
Step 4
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