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In the diagram below, the graph of $f(x) = -2 ext{sin} x$ is drawn for the interval $x orall [-180^{ ext{o}} ; 180^{ ext{o}}].$ 7.1 On the grid provided in the ANSWER BOOK, draw the graph of $g(x) = ext{cos}(x - 60^{ ext{o}})$ for $x orall [-180^{ ext{o}} ; 180^{ ext{o}}]$ - NSC Mathematics - Question 7 - 2021 - Paper 2

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Question 7

In-the-diagram-below,-the-graph-of-$f(x)-=--2-ext{sin}-x$-is-drawn-for-the-interval-$x--orall-[-180^{-ext{o}}-;-180^{-ext{o}}].$--7.1-On-the-grid-provided-in-the-ANSWER-BOOK,-draw-the-graph-of-$g(x)-=--ext{cos}(x---60^{-ext{o}})$-for-$x--orall-[-180^{-ext{o}}-;-180^{-ext{o}}]$-NSC Mathematics-Question 7-2021-Paper 2.png

In the diagram below, the graph of $f(x) = -2 ext{sin} x$ is drawn for the interval $x orall [-180^{ ext{o}} ; 180^{ ext{o}}].$ 7.1 On the grid provided in the ANS... show full transcript

Worked Solution & Example Answer:In the diagram below, the graph of $f(x) = -2 ext{sin} x$ is drawn for the interval $x orall [-180^{ ext{o}} ; 180^{ ext{o}}].$ 7.1 On the grid provided in the ANSWER BOOK, draw the graph of $g(x) = ext{cos}(x - 60^{ ext{o}})$ for $x orall [-180^{ ext{o}} ; 180^{ ext{o}}]$ - NSC Mathematics - Question 7 - 2021 - Paper 2

Step 1

7.1 On the grid provided in the ANSWER BOOK, draw the graph of $g(x) = ext{cos}(x - 60^{ ext{o}})$ for $x orall [-180^{ ext{o}} ; 180^{ ext{o}}]$

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Answer

To draw the graph of g(x)=extcos(x60exto)g(x) = ext{cos}(x - 60^{ ext{o}}):

  1. Start by noting the amplitude, which is 1.
  2. The phase shift is to the right by 60°.
  3. Plot key points:
    • The function has a maximum at x=60extox = 60^{ ext{o}}.
    • The first x-intercept occurs at x=60exto+90exto=150extox = 60^{ ext{o}} + 90^{ ext{o}} = 150^{ ext{o}}.
    • The second x-intercept occurs at x=60exto90exto=30extox = 60^{ ext{o}} - 90^{ ext{o}} = -30^{ ext{o}}.
  4. Draw the graph, ensuring to include both turning points and the specified x-intercepts.

Step 2

7.2 Write down the period of $f(3x)$

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Answer

The period of a sine function is calculated through the formula: ext{Period} = rac{360^{ ext{o}}}{|B|} where BB is the coefficient of xx in f(x)=2extsin(3x)f(x) = -2 ext{sin}(3x). In this case, B=3B = 3, thus the period of f(3x)f(3x) is: ext{Period} = rac{360^{ ext{o}}}{3} = 120^{ ext{o}}

Step 3

7.3 Use the graphs to determine the value of $x$, if $x orall [-180^{ ext{o}} ; 180^{ ext{o}}]$ for which $f(x) = g(x) = 1$

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Answer

From the graphs:

  • f(x)f(x) reaches its maximum value of 1 at x=90extox = -90^{ ext{o}}.
  • g(x)g(x) achieves its maximum value of 1 at x=150extox = 150^{ ext{o}}.

Hence, we find: x=30extox = -30^{ ext{o}}

Step 4

7.4 Write down the range of $k$, if $k(x) = rac{1}{2} g(x) + 1$

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Answer

For g(x)g(x), the function varies between -1 and 1 over the specified interval:

  • Minimum of g(x) = -1 ightarrow k(x) = rac{1}{2}(-1) + 1 = rac{1}{2}.
  • Maximum of g(x) = 1 ightarrow k(x) = rac{1}{2}(1) + 1 = rac{3}{2}. Therefore, the range of kk is:
ightarrow rac{3}{2}$$

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