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7.1 Define swept volume of an engine - NSC Mechanical Technology Automotive - Question 7 - 2022 - Paper 1

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7.1 Define swept volume of an engine. 7.2 A car with a mass of 980 kg is hoisted to a height of 35 m. Calculate the work done in kJ. 7.3 FIGURE 7.3 below shows a c... show full transcript

Worked Solution & Example Answer:7.1 Define swept volume of an engine - NSC Mechanical Technology Automotive - Question 7 - 2022 - Paper 1

Step 1

7.3.1 Name distances A and B.

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Answer

The distances are defined as follows:

  • Distance A: Bore or cylinder diameter.
  • Distance B: Stroke length.

Step 2

7.3.2 Calculate the swept volume in cm³ when A = 120 mm and B = 135 mm.

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Answer

To calculate the swept volume (SV), we can use the formula:

SV = rac{ ext{π} imes D^2}{4} imes L

Where:

  • D is the bore (diameter) in cm
  • L is the stroke length in cm.

For this question:

  • D = 12 cm (120 mm converted to cm)
  • L = 13.5 cm (135 mm converted to cm)

Plugging in the values:

SV = rac{ ext{π} imes (12)^2}{4} imes 13.5 = rac{3.1416 imes 144}{4} imes 13.5 \ = 1,526.81 ext{ cm}^3

Step 3

7.3.3 Calculate the compression ratio of this engine if the clearance volume is 102,5 cm³.

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Answer

The compression ratio (CR) is calculated using the following formula:

CR = rac{SV + CV}{CV}

Where:

  • SV is the swept volume calculated earlier as 1,526.81 cm³
  • CV is the clearance volume, given as 102.5 cm³.

Substituting the values:

CR = rac{1,526.81 + 102.5}{102.5} = rac{1,629.31}{102.5} \ = 15.9:1

Step 4

7.4 Calculate the indicated power developed in a four-stroke four-cylinder engine at 1 800 r/min.

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Answer

The indicated power can be calculated using the following relation:

P = rac{(P_{m} imes L imes A imes N)}{60} imes n

Where:

  • P_{m} is the mean effective pressure (1,150 kPa, convert to Pa)
  • L is stroke length in meters (0.077 m for 77 mm)
  • A is the cross-sectional area of the cylinder:
A = rac{ ext{π} imes D^2}{4} = rac{3.1416 imes (0.1)^2}{4} = 7.85 imes 10^{-3} m^2
  • N is number of revolutions per minute (1,800 r/min)
  • n is number of cylinders (4)

Substituting values and calculating the power:

P = rac{(1,150,000 imes 0.077 imes 7.85 imes 10^{-3} imes 1,800)}{60} imes 4 = 157.08 kW

Step 5

7.6.1 Torque of the brake arm.

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Answer

The torque ( au) can be calculated using the formula:

au=extForceimesextradius au = ext{Force} imes ext{radius}

Where the force is the weight:

extForce=mimesg=120imes10=1200N ext{Force} = m imes g = 120 imes 10 = 1200 N

And the radius in meters is:

ext{radius} = rac{500}{1000} = 0.5 m

Thus,

au=1200imes0.5=600Nm au = 1200 imes 0.5 = 600 Nm

Step 6

7.6.2 Power developed by the engine in kW.

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Answer

The brake power can be calculated using the formula:

PB=2imesextπimesnimesauP_{B} = 2 imes ext{π} imes n imes au

Substituting the values:

  • n = 2500 r/min (RPM here indicates revolution per minute)
  • au = 600 Nm

Thus,

P_{B} = 2 imes 3.1416 imes rac{2500}{60} imes 600= 157.08 kW

Step 7

7.6.3 Mechanical efficiency if the indicated power is 196 kW.

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Answer

Mechanical efficiency ( ext{ME}) can be calculated by the formula:

ext{ME} = rac{B.P}{I.P} imes 100

Substituting the values:

  • Brake power (B.P) = 157.08 kW
  • Indicated power (I.P) = 196 kW

Thus,

ext{ME} = rac{157.08}{196} imes 100 \ ext{ME} ext{ approximately equals } 80.14 \%

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