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FIGURE 5.1 below shows the set-up of a taper with an included angle of 8°, to be machined between centres - NSC Mechanical Technology Fitting and Machining - Question 5 - 2019 - Paper 1

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FIGURE-5.1-below-shows-the-set-up-of-a-taper-with-an-included-angle-of-8°,-to-be-machined-between-centres-NSC Mechanical Technology Fitting and Machining-Question 5-2019-Paper 1.png

FIGURE 5.1 below shows the set-up of a taper with an included angle of 8°, to be machined between centres. 5.1.1 Calculate the small diameter (d) of the taper. 5.1... show full transcript

Worked Solution & Example Answer:FIGURE 5.1 below shows the set-up of a taper with an included angle of 8°, to be machined between centres - NSC Mechanical Technology Fitting and Machining - Question 5 - 2019 - Paper 1

Step 1

Calculate the small diameter (d) of the taper.

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Answer

To find the small diameter (d) of the taper, we begin by establishing the relationship between the large diameter (D), the small diameter (d), and the length (L) of the taper.

The formula for the diameter at a distance from the larger end can be derived using trigonometric relations. Given the angle θ and length:

Using the formula:

an rac{ heta}{2} = \frac{d - D}{L}

Here, substituting the values:

  • D=200extmmD = 200 ext{ mm} (large diameter)
  • L=300extmmL = 300 ext{ mm}
  • heta=8° heta = 8° gives a tangent: an4°0.06976 an 4° \approx 0.06976

Calculating:

AB=an4°×30020.98extmmAB = an 4° \times 300 \approx 20.98 ext{ mm}

Now, substituting into the formula for the small diameter:

d=D2ABd = D - 2AB d=2002(20.98)extmmd = 200 - 2(20.98) ext{ mm} d158.04extmmd \approx 158.04 ext{ mm}

Therefore, the small diameter (d) of the taper is approximately 158.04 mm.

Step 2

Calculate the tailstock set-over required for cutting the taper in FIGURE 5.1.

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Answer

To calculate the tailstock set-over, we use the set-over angle determined in the previous calculation.

Given that the set-over can be found using the relationship:

X=ABL×300X = \frac{AB}{L} \times 300

Substituting the values:

  • AB20.98extmmAB \approx 20.98 ext{ mm}
  • L=300extmmL = 300 ext{ mm}

Then,

X=20.98300×40027.97extmmX = \frac{20.98}{300} \times 400 \approx 27.97 ext{ mm}

Thus, the tailstock set-over required is approximately 27.97 mm.

Step 3

Width

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Answer

To find the width of the parallel key:

Width=D4\text{Width} = \frac{D}{4}

Given: D=42extmmD = 42 ext{ mm},

Substituting:

Width=424=10.5extmm\text{Width} = \frac{42}{4} = 10.5 ext{ mm}

The width of the key is 10.5 mm.

Step 4

Thickness

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Answer

To find the thickness of the parallel key:

Thickness=D6\text{Thickness} = \frac{D}{6}

Given: D=42extmmD = 42 ext{ mm},

Substituting:

Thickness=426=7extmm\text{Thickness} = \frac{42}{6} = 7 ext{ mm}

The thickness of the key is 7 mm.

Step 5

State TWO advantages of down-cut milling.

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Answer

  1. A better finish is obtained due to the cutting action slicing down into the material, which reduces the friction.

  2. High-speed cutting is possible, which leads to more efficient machining processes and allows for deeper cuts to be made.

Step 6

Use a neatly labelled sketch to show straddle milling.

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Answer

To illustrate straddle milling, depict a setup with two milling cutters positioned either side of a workpiece. Ensure to label the following parts:

  • Arbor
  • Work piece
  • Milling cutters

This setup allows simultaneous cutting on both sides of the workpiece, enhancing efficiency.

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