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FIGURE 8.1 below shows a system of four forces acting on the same point - NSC Mechanical Technology Fitting and Machining - Question 8 - 2022 - Paper 1

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FIGURE 8.1 below shows a system of four forces acting on the same point. Answer the questions that follow. HINT: Draw and complete the diagram for the forces shown ... show full transcript

Worked Solution & Example Answer:FIGURE 8.1 below shows a system of four forces acting on the same point - NSC Mechanical Technology Fitting and Machining - Question 8 - 2022 - Paper 1

Step 1

8.1.1 The sum of the horizontal components

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Answer

To find the sum of the horizontal components, we analyze the forces acting horizontally:

  • The horizontal component of the 120 N force at an angle of 70° is given by: = 120 imes 0.342 = 41.04 \, N$$
  • The horizontal component of the 55 N force at an angle of 60° is: = 55 imes 0.5 = 27.5 \, N$$

Thus, the total horizontal components: extTotalhorizontal=41.04N+27.5N=68.54N ext{Total horizontal} = 41.04 \, N + 27.5 \, N = 68.54 \, N

Step 2

8.1.2 The sum of the vertical components

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Answer

For the vertical components, we consider:

  • The vertical component of the 25 N force is: 25N25 \, N

  • The vertical component of the 40 N force is: 40N40 \, N

  • The vertical component of the 120 N force:

    = 120 imes 0.940 = 112.8 \, N$$
  • The vertical component of the 55 N force:

    = 55 imes 0.866 = 47.63 \, N$$

Combining these: extTotalvertical=25+40+112.8+47.63=225.43N ext{Total vertical} = 25 + 40 + 112.8 + 47.63 = 225.43 \, N

Step 3

8.1.3 The magnitude of the resultant

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Answer

The magnitude of the resultant vector can be calculated using:

= ext{sqrt}(68.54^2 + 225.43^2) \\ = ext{sqrt}(4693.8116 + 50880.0649) \\ = ext{sqrt}(55573.8765) \\ = 235.77 \, N$$

Step 4

8.1.4 The angle and direction of the resultant

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Answer

The angle of the resultant can be found using:

= an^{-1}igg( rac{225.43}{68.54}igg) \\ = an^{-1}(3.29) \\ heta \\ ext{Angle} = 73.2°$$ Thus, the direction of the resultant is 73.2° above the horizontal.

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