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6.1 A spur gear with 50 teeth has a module of 3 - NSC Mechanical Technology Fitting and Machining - Question 6 - 2018 - Paper 1

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6.1 A spur gear with 50 teeth has a module of 3. Calculate the cordal tooth thickness of the gear teeth. 6.2 Calculate the required simple indexing to cut a gear wi... show full transcript

Worked Solution & Example Answer:6.1 A spur gear with 50 teeth has a module of 3 - NSC Mechanical Technology Fitting and Machining - Question 6 - 2018 - Paper 1

Step 1

Calculate the cordal tooth thickness of the gear teeth.

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Answer

To find the cordal tooth thickness (tct_c), use the formula:$

t_c = rac{T}{2} imes ext{sin} rac{90°}{T} $ Where:

  • TT = Number of teeth.

Plugging in the values:

  • For 5050 teeth:
egin{align*} ext{Using } T = 50\ \ t_c = rac{50}{2} imes ext{sin} rac{90°}{50} = 4.71 ext{ mm} ext{or} \ t_c = PCD imes ext{sin} rac{90°}{T} \ = rac{150}{50} imes 0.03141 \ = 4.71 ext{ mm} ext{So the cordal tooth thickness is approximately 4.71 mm.} ext{Final Answer: } t_c ext{ = 4.71 mm}

Step 2

Calculate the required simple indexing.

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Answer

To calculate simple indexing for a gear with 13 teeth,

  • Use the formula for simple indexing:
ext{Simple indexing } = 40 imes rac{N}{ ext{number of turns}}

With N = 40 and the number of teeth = 13:

  • After determining parameters, set up for 39 hole circle as follows:
=3extfullturnsand3holesina39holecircle.= 3 ext{ full turns and 3 holes in a 39 hole circle.}

Step 3

The differential indexing required (Choose 125 teeth.)

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Answer

For differential indexing:

  • Using the relation:
ext{Indexing } = rac{40}{40} - rac{n}{N} \ N = 127, ext{ thus = } rac{40}{40} - rac{127}{125}

Solving this gives:

  • Required differential indexing for 125 teeth is 88 holes on the 2525 hole circle.

Step 4

The change gears required

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Answer

The change gears can be calculated by:

D_r = rac{A_n imes D}{40} \ D_r = 125 - 127 imes rac{40}{125}

Solving, we find:

  • Change gears required = 64 ratios 100.

Step 5

The direction of rotation of the index plate in relation to the index crank handle.

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Answer

The index plate will turn in the opposite direction to that of the index crank handle.

Step 6

Calculate distance X between the rollers in FIGURE 6.4.

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Answer

To calculate distance XX:

  1. Use the geometric relationships:
x = 150 + 2(AB) - 2(CD) - 2r\
  1. Here, with given values and utilizing tan properties:
  • Obtain xx:
=150+2(20.21)2(25.98)30=108.454extmm= 150 + 2(20.21) - 2(25.98) - 30 = 108.454 ext{ mm}

Step 7

Give TWO reasons why a work piece must be balanced on a centre lathe when a face plate is used.

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Answer

  1. To prevent unnecessary bearing loads.
  2. To avoid excessive vibrations.

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