'n Twee-gang vierkantige skroefraadstaaf moet vervaardig word - NSC Mechanical Technology Fitting and Machining - Question 10 - 2021 - Paper 1
Question 10
'n Twee-gang vierkantige skroefraadstaaf moet vervaardig word. Die stygting van die skroefraad is 40 mm en die kruindiameter is 85 mm. Die vrylpohoek moet 3° wees.
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Worked Solution & Example Answer:'n Twee-gang vierkantige skroefraadstaaf moet vervaardig word - NSC Mechanical Technology Fitting and Machining - Question 10 - 2021 - Paper 1
Step 1
10.1.1 Gemiddelde diameter
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Answer
To calculate the mean diameter (
D_m), we use the formula:
D_m = D_{OD} - rac{P}{2}
Where:
DOD=85extmm
P (Pitch) = 40 mm
Using the number of starts = 2:
Thus,
Dm=85−240=75extmm
Therefore, the mean diameter is 75 mm.
Step 2
10.1.2 Helikshoek van die skroefraad
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Answer
The helix angle (θ) can be calculated using the formula:
tan(θ)=π×DmLead
Where the lead is equal to the pitch (40 mm). Therefore:
tan(θ)=π×7540
Calculating this gives:
θ=tan−1(0.169765272)≈9.63° or 9°38′
Step 3
10.1.3 Ingryphoek (Voorsnyhoek) van die beitel
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Answer
The leading tool angle is given by the formula:
Leading tool angle=90°+helix angle+clearance angle
Substituting:
Helix angle = 9.63°
Clearance angle = 3°:
Leading tool angle=90°+9.63°+3°=77.37°extor77°22′
Step 4
10.1.4 Sleephoek (Nasnyhoek) van die beitel
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Answer
The following tool angle is calculated using:
Following tool angle=90°+helix angle−clearance angle
Substituting:
Helix angle = 9.63°
Clearance angle = 3°:
Following tool angle=90°+9.63°−3°=96.63° or 96°38′
Step 5
10.2 Benoen A–D
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Answer
A. Pitch diameter/mean/effective
B. Helix angle
C. Pitch/Lead
D. Root/Root length
Step 6
10.3 Noem TWEE gebruike van 'n vierkantige skroefraad
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