Photo AI

Calculate the following: 11.1.1 The fluid pressure in the hydraulic system in MPa 11.1.2 The diameter in millimeters of piston B 11.2 State TWO advantages of a chain drive when compared to a belt drive - NSC Mechanical Technology Fitting and Machining - Question 11 - 2021 - Paper 1

Question icon

Question 11

Calculate-the-following:--11.1.1-The-fluid-pressure-in-the-hydraulic-system-in-MPa--11.1.2-The-diameter-in-millimeters-of-piston-B--11.2-State-TWO-advantages-of-a-chain-drive-when-compared-to-a-belt-drive-NSC Mechanical Technology Fitting and Machining-Question 11-2021-Paper 1.png

Calculate the following: 11.1.1 The fluid pressure in the hydraulic system in MPa 11.1.2 The diameter in millimeters of piston B 11.2 State TWO advantages of a ch... show full transcript

Worked Solution & Example Answer:Calculate the following: 11.1.1 The fluid pressure in the hydraulic system in MPa 11.1.2 The diameter in millimeters of piston B 11.2 State TWO advantages of a chain drive when compared to a belt drive - NSC Mechanical Technology Fitting and Machining - Question 11 - 2021 - Paper 1

Step 1

11.1.1 The fluid pressure in the hydraulic system in MPa

96%

114 rated

Answer

To calculate the fluid pressure in the hydraulic system, we can use the formula:

P=FAP = \frac{F}{A}

Where:

  • FF is the force applied.
  • AA is the cross-sectional area of piston A.

First, we need to find the area of piston A:

AA=πDA24=π(0.025)240.0004909m2A_A = \frac{\pi D_A^2}{4} = \frac{\pi (0.025)^2}{4} \approx 0.0004909 \, m^2

Now, substituting the force and area:

P=1.32×103N0.0004909m22.69×106Pa=2.69MPaP = \frac{1.32 \times 10^3 \, N}{0.0004909 \, m^2} \approx 2.69 \times 10^6 \, Pa = 2.69 \, MPa

Step 2

11.1.2 The diameter in millimeters of piston B

99%

104 rated

Answer

To find the diameter of piston B, we need to equate the pressures in both pistons:

PA=PBP_A = P_B

Where:

PB=FBABP_B = \frac{F_B}{A_B}

Using the area formula:

AB=πDB24A_B = \frac{\pi D_B^2}{4}

Given:

  • FB=6.45×103NF_B = 6.45 \times 10^3 \, N
  • PA=2.69imes106PaP_A = 2.69 imes 10^6 \, Pa

Setting the pressure equal:

2.69×106=FBπDB242.69 \times 10^6 = \frac{F_B}{\frac{\pi D_B^2}{4}}

Solving for DBD_B gives:

DB55.28mmD_B \approx 55.28 \, mm

Step 3

11.2 State TWO advantages of a chain drive when compared to a belt drive.

96%

101 rated

Answer

  1. Higher Efficiency: Chain drives typically have lower power losses compared to belt drives due to reduced slippage, making them more efficient for power transmission.

  2. Better Load Handling: Chain drives can handle heavy loads better than belt drives, allowing them to be used in applications where high torque is required without slipping.

Step 4

11.3 State TWO functions of a reservoir in a hydraulic system.

98%

120 rated

Answer

  1. Fluid Storage: A hydraulic reservoir stores the hydraulic fluid, ensuring there is enough fluid available for the system to operate efficiently.

  2. Heat Dissipation: It helps in dissipating heat generated during application, maintaining the fluid temperature within the operational range.

Step 5

11.4 State ONE application of a hydraulic system.

97%

117 rated

Answer

One common application of hydraulic systems is in excavators, where hydraulic power is used to lift and operate the digging arm.

Join the NSC students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;